Problem
How to swap the numbers using the bitwise operator in the C programming language?
Solution
The compiler swap the given numbers, first, it converts the given decimal number into binary equivalent then it performs a bitwise XOR operation to exchange the numbers from one memory location to another.
Algorithm
START Step 1: declare two variables a and b Step 1: Enter two numbers from console Step 2: swap two numbers by using BITWISE operator a=a^b b=a^b a=a^b Step 3: Print a and b values STOP
Program
#include<stdio.h> int main(){ int a,b; printf("enter the values for a and b:"); scanf("%d%d",&a,&b); printf("value of a=%d and b=%d before swap\n",a,b); a= a^b; b= a^b; a= a^b; printf("value of a=%d and b=%d after swap",a,b); return 0; }
Output
enter the values for a and b:24 56 value of a=24 and b=56 before swap value of a=56 and b=24 after swap Explanation: a=24 binary equivalent of 24 =011000 b=56 binary equivalent of 56= 111000 a= a^b = 100000 b=a^b=100000 ^ 111000 =011000 a=a^b=100000 ^ 011000 = 111000 Now a=111000 decimal equivalent =56 b= 011000 decimal equivalent = 24