Problem
Write a C program to display and add the elements using dynamic memory allocation functions.
Solution
In C, the library function malloc allocates a block of memory in bytes at runtime. It returns a void pointer, which points to the base address of allocated memory and it leaves the memory uninitialized.
Syntax
void *malloc (size in bytes)
For example,
int *ptr;
ptr = (int * ) malloc (1000);
int *ptr;
ptr = (int * ) malloc (n * sizeof (int));
Note − It returns NULL, if the memory is not free.
Example
#include<stdio.h> #include<stdlib.h> void main(){ //Declaring variables and pointers,sum// int numofe,i,sum=0; int *p; //Reading number of elements from user// printf("Enter the number of elements : "); scanf("%d",&numofe); //Calling malloc() function// p=(int *)malloc(numofe*sizeof(int)); /*Printing O/p - We have to use if statement because we have to check if memory has been successfully allocated/reserved or not*/ if (p==NULL){ printf("Memory not available"); exit(0); } //Printing elements// printf("Enter the elements : \n"); for(i=0;i<numofe;i++){ scanf("%d",p+i); sum=sum+*(p+i); } printf("\nThe sum of elements is %d",sum); free(p);//Erase first 2 memory locations// printf("\nDisplaying the cleared out memory location : \n"); for(i=0;i<numofe;i++){ printf("%d\n",p[i]);//Garbage values will be displayed// } }
Output
Enter the number of elements : 5 Enter the elements : 23 45 65 12 23 The sum of elements is 168 Displaying the cleared out memory location : 10753152 0 10748240 0 23