Problem
Remove all the extra spaces from an entered string at runtime with the help of while loop by checking the spaces at each index of a character.
Solution
Consider an example given below −
It removes all the spaces from a given string. The given string is Tutorials Point C Programming. The result after removing spaces is TutorialsPointCProgramming.
An array of characters is called a string.
Given below is the declaration of a string −
char stringname [size];
For example, char string[50]; string of length 50 characters.
Initialization
- Using single character constant.
char string[10] = { ‘H’, ‘e’, ‘l’, ‘l’, ‘o’ ,‘\0’}
- Using string constants.
char string[10] = “Hello”:;
Accessing
There is a control string “%s” used for accessing the string till it encounters ‘\0’.
The logic we used to remove extra spaces between strings is as follows −
len = strlen(string); for(i=0; i<len; i++){ if(string[0]==' '){ for(i=0; i<(len-1); i++) string[i] = string[i+1]; string[i] = '\0'; len--; i = -1; continue; } if(string[i]==' ' && string[i+1]==' '){ for(j=i; j<(len-1); j++){ string[j] = string[j+1]; } string[j] = '\0'; len--; i--; } }
Example
Following is the C program to remove all the extra spaces in a sentence by using the string concepts −
#include<stdio.h> int main() { char string[200]; int i, j, len; printf("Enter a statement: "); gets(string); len = strlen(string); for(i=0; i<len; i++) { if(string[0]==' ') { for(i=0; i<(len-1); i++) string[i] = string[i+1]; string[i] = '\0'; len--; i = -1; continue; } if(string[i]==' ' && string[i+1]==' ') { for(j=i; j<(len-1); j++) { string[j] = string[j+1]; } string[j] = '\0'; len--; i--; } } printf("\nNew String after removing extra spaces is = %s", string); getch(); return 0; }
Output
When the above program is executed, it produces the following output −
Enter a statement: Welcome to The world of C programming New String after removing extra spaces is = Welcome to The world of C programming