C program to sort an array in descending order

Problem

Sort the given array in descending or ascending order based on the code that has been written.

Solution

An array is a group of related data items which share’s a common name. A particular value in an array is identified with the help of its "index number".

Declaring array

The syntax for declaring an array is as follows −

datatype array_name [size];

For example,

float marks [50]

It declares ‘marks’ to be an array containing 50 float elements.

int number[10]

It declares the ‘number’ as an array to contain a maximum of 10 integer constants.

Each element is identified by using an "array index".

Accessing array elements is easy by using the array index.

Program

Following is the C program to sort an array in descending order −

#include <stdio.h>
void main (){
   int num[20];
   int i, j, a, n;
   printf("enter number of elements in an array\n");
   scanf("%d", &n);
   printf("Enter the elements\n");
   for (i = 0; i < n; ++i)
      scanf("%d", &num[i]);
   for (i = 0; i < n; ++i){
      for (j = i + 1; j < n; ++j){
         if (num[i] < num[j]){
            a = num[i];
            num[i] = num[j];
            num[j] = a;
         }
      }
   }
   printf("The numbers in descending order is:\n");
   for (i = 0; i < n; ++i){
      printf("%d\n", num[i]);
   }
}

Output

When the above program is executed, it produces the following result −

enter number of elements in an array
4
Enter the elements
11
34
67
89
The numbers in descending order is:
89
67
34
11