Problem
A program to print Excel column title that corresponds to a given column number (integer value). User has to enter the integer number based on given number it has to print excel column number.
Solution
The solution to print Excel column title that corresponds to a given column number in C programming language is explained below −
Example 1
Let us see an example.
1 -> A 2 -> B ... 26 -> Z 27 -> AA 28 -> AB ...
Example 2
- The input is as follows −
number = 3 number = 27 number = 151
- The output is as follows −
Excel column title: C Excel column title: AA Excel column title: EU
Example
Following is the C program to print the Excel column title that corresponds to a given column number −
#include <stdio.h>
static char *convert_To_Excel_Title(int column_no){
if (column_no <= 0) {
return "";
}
char *result = malloc(1024);
int len = 0;
do {
result[len++] = ((column_no - 1) % 26) + 'A';
column_no = (column_no - 1) / 26;
} while (column_no > 0);
result[len] = '\0';
int i, j;
for (i = 0, j = len - 1; i < j; i++, j--) {
char c = result[i];
result[i] = result[j];
result[j] = c;
}
return result;
}
int main(void){
int n;
printf("enter the integer1:");
scanf("%d",&n);
printf("Column Number n = %d", n);
printf("\nExcel column title: %s\n\n ",convert_To_Excel_Title(n));
printf("enter the integer2:");
scanf("%d",&n);
printf("\nColumn Number n = %d", n);
printf("\nExcel column title: %s\n\n ",convert_To_Excel_Title(n));
printf("enter the integer3:");
scanf("%d",&n);
printf("\n\nColumn Number n = %d", n);
printf("\nExcel column title: %s ",convert_To_Excel_Title(n));
return 0;
}Output
When the above program is executed, it produces the following result −
enter the integer1:23 Column Number n = 23 Excel column title: W enter the integer2:12 Column Number n = 12 Excel column title: L enter the integer3:69 Column Number n = 69 Excel column title: BQ