Suppose we have a number n. We shall have to make an array of size n dynamically and take n numbers one by one, then find the sum. To make the array we can use malloc() or calloc() function which is present inside the stdlib.h header file. The value of n is also provided as input through stdin.
So, if the input is like n = 6, and array elements 9, 8, 7, 2, 4, 3, then the output will be 33 because sum of 9 + 8 + 7 + 2 + 4 + 3 = 33.
To solve this, we will follow these steps −
sum := 0
take one input and store it to n
arr := dynamically create an array of size n
for initialize i := 0, when i < n, update (increase i by 1), do:
take an input and store it to arr[i]
for initialize i := 0, when i < n, update (increase i by 1), do:
sum := sum + arr[i]
return sum
Example
Let us see the following implementation to get better understanding −
#include <stdio.h>
#include <stdlib.h>
int main(){
int *arr;
int n;
int sum = 0;
scanf("%d", &n);
arr = (int*) malloc(n*sizeof(int));
for(int i = 0; i < n; i++){
scanf("%d", (arr+i));
}
for(int i = 0; i < n; i++){
sum += arr[i];
}
printf("%d", sum);
}
Input
6 9 8 7 2 4 3
Output
33