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Strobogrammatic Number II in C++
Suppose we have a length n. We have to find all strobogrammatic numbers that are of length n.
As we know that a strobogrammatic number is a number that looks the same when rotated 180 degrees.
So, if the input is like n = 2, then the output will be ["11","69","88","96"]
To solve this, we will follow these steps −
Define an array ret
-
if n is odd, then −
insert "0" at the end of ret
insert "1" at the end of ret
insert "8" at the end of ret
-
Otherwise
insert blank string at the end of ret
-
for n > 1, update n := n - 2, do −
Define an array temp
-
for initialize i := 0, when i < size of ret, update (increase i by 1), do −
s := ret[i]
-
if n > 3, then −
insert "0" concatenate s concatenate "0" at the end of temp
insert "1" concatenate s concatenate "1" at the end of temp
insert "8" concatenate s concatenate "8" at the end of temp
insert "6" concatenate s concatenate "9" at the end of temp
insert "9" concatenate s concatenate "6" at the end of temp
ret := temp
return ret
Example
Let us see the following implementation to get a better understanding −
#include <bits/stdc++.h> using namespace std; void print_vector(vector<auto< v){ cout << "["; for(int i = 0; i<v.size(); i++){ cout << v[i] << ", "; } cout << "]"<<endl; } class Solution { public: vector<string< findStrobogrammatic(int n) { vector<string< ret; if (n & 1) { ret.push_back("0"); ret.push_back("1"); ret.push_back("8"); } else { ret.push_back(""); } for (; n > 1; n -= 2) { vector<string< temp; for (int i = 0; i < ret.size(); i++) { string s = ret[i]; if (n > 3) { temp.push_back("0" + s + "0"); } temp.push_back("1" + s + "1"); temp.push_back("8" + s + "8"); temp.push_back("6" + s + "9"); temp.push_back("9" + s + "6"); } ret = temp; } return ret; } }; main(){ Solution ob; print_vector(ob.findStrobogrammatic(3)); }
Input
3
Output
[101, 808, 609, 906, 111, 818, 619, 916, 181, 888, 689, 986, ]