Replace Multiple of 3 and 5 with Fizz Buzz in Python

Suppose we have a number n. We have to find a string that is representing all numbers from 1 to n, but we have to follow some rules.

• When the number is divisible by 3, put Fizz instead of the number

• When the number is divisible by 5, put Buzz instead of the number

• When the number is divisible by 3 and 5 both, put FizzBuzz instead of the number

To solve this, we will follow these steps −

• For all number from 1 to n,
  • if number is divisible by 3 and 5 both, put “FizzBuzz”
  • otherwise when number is divisible by 3, put “Fizz”
  • otherwise when number is divisible by 5, put “Buzz”
  • otherwise write the number as string

Let us see the following implementation to get better understanding −

Example

 Live Demo

class Solution(object):
   def fizzBuzz(self, n):
      result = []
      for i in range(1,n+1):
         if i% 3== 0 and i%5==0:
            result.append("FizzBuzz")
         elif i %3==0:
            result.append("Fizz")
         elif i% 5 == 0:
            result.append("Buzz")
         else:
            result.append(str(i))
      return result
ob1 = Solution()
print(ob1.fizzBuzz(15))

Input

15

Output

['1', '2', 'Fizz', '4', 'Buzz', 'Fizz', '7', '8', 'Fizz', 'Buzz', '11', 'Fizz', '13', '14', 'FizzBuzz']