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Check Whether Parentheses are Balanced in Python
Suppose we have a string s consisting of parenthesis "(" and ")". We have to check whether the parentheses are balanced or not.
So, if the input is like s = "(()())(())", then the output will be True
To solve this, we will follow these steps −
- num_open := 0
- for each character c in s, do
- if c is same as ')', then
- if num_open < 0, then
- num_open := num_open - 1
- otherwise,
- return False
- otherwise,
- num_open := num_open + 1
- if num_open < 0, then
- if c is same as ')', then
- return inverse of num_open
Let us see the following implementation to get better understanding −
Example
class Solution: def solve(self, s): num_open = 0 for c in s: if c == ')': if num_open < 0: num_open -= 1 else: return False else: num_open += 1 return not num_open ob = Solution() print(ob.solve("(()())(())"))
Input
"(()())(())"
Output
False
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