Check for Three Consecutive Odds in Python

Suppose we have an array called nums, we have to check whether there are three consecutive odd numbers in nums or not.

So, if the input is like nums = [18,15,2,19,3,11,17,25,20], then the output will be True as there are three consecutive odds [3,11,17].

To solve this, we will follow these steps −

• length:= size of nums

• if length is same as 1 or length is same as 2, then

  • return False

• otherwise,

  • for i in range 0 to size of nums - 3, do

    • if nums[i], nums[i+1] and nums[i+2] all are odds, then

      • return True

• return False

Example (Python)

Let us see the following implementation to get better understanding −

 Live Demo

def solve(nums):
   length=len(nums)
   if length==1 or length ==2:
      return False
   else:
      for i in range(len(nums)-2):
         if nums[i] % 2 != 0 and nums[i+1] % 2 != 0 and nums[i+2] % 2 != 0:
            return True
      return False

nums = [18,15,2,19,3,11,17,25,20]
print(solve(nums))

Input

[18,15,2,19,3,11,17,25,20]

Output

True