Order and Display Date Differences from Current Date in MySQL

For this, use ORDER BY clause. The current date is as follows −

mysql> select now();
+---------------------+
| now()               |
+---------------------+
| 2019-06-09 21:08:16 |
+---------------------+
1 row in set (0.00 sec)

Let us first create a table −

mysql> create table DemoTable
   -> (
   -> Id int NOT NULL AUTO_INCREMENT PRIMARY KEY,
   -> DueDate datetime
   -> );
Query OK, 0 rows affected (0.62 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable(DueDate) values('2019-06-12');
Query OK, 1 row affected (0.24 sec)

mysql> insert into DemoTable(DueDate) values('2019-06-01');
Query OK, 1 row affected (0.37 sec)

mysql> insert into DemoTable(DueDate) values('2019-06-05');
Query OK, 1 row affected (0.20 sec)

mysql> insert into DemoTable(DueDate) values('2019-06-10');
Query OK, 1 row affected (0.13 sec)

mysql> insert into DemoTable(DueDate) values('2019-06-11');
Query OK, 1 row affected (0.66 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable;

Output

+----+---------------------+
| Id | DueDate             |
+----+---------------------+
| 1  | 2019-06-12 00:00:00 |
| 2  | 2019-06-01 00:00:00 |
| 3  | 2019-06-05 00:00:00 |
| 4  | 2019-06-10 00:00:00 |
| 5  | 2019-06-11 00:00:00 |
+----+---------------------+
5 rows in set (0.00 sec)

Here is the query to order by to get the difference and order the dates. The difference between the dates are displayed in a separate column −

mysql> select Id,DueDate,DATEDIFF(DueDate, CURDATE()) AS t from DemoTable
   -> order by CASE WHEN t < 0 THEN 1 ELSE 0 END, t;

Output

+----+---------------------+------+
| Id | DueDate             | t    |
+----+---------------------+------+
| 4  | 2019-06-10 00:00:00 | 1    |
| 5  | 2019-06-11 00:00:00 | 2    |
| 1  | 2019-06-12 00:00:00 | 3    |
| 2  | 2019-06-01 00:00:00 | -8   |
| 3  | 2019-06-05 00:00:00 | -4   |
+----+---------------------+------+
5 rows in set (0.00 sec)