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MySQL Query to Count Values and Display in New Column Descending
Use ORDER BY with DESC to order in descending order. For counting the values, use the COUNT(). For example, if the name “John” appears thrice in the column, then a separate column will display the count 3 and in this way all the count values will be arranged in descending order using the ORDER BY DESC.
Let us first create a table −
mysql> create table DemoTable -> ( -> EmployeeName varchar(100) -> ); Query OK, 0 rows affected (0.85 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable values('Sam'); Query OK, 1 row affected (0.17 sec) mysql> insert into DemoTable values('David'); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable values('David'); Query OK, 1 row affected (0.31 sec) mysql> insert into DemoTable values('Chris'); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable values('Robert'); Query OK, 1 row affected (0.11 sec) mysql> insert into DemoTable values('Chris'); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable values('Sam'); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable values('Sam'); Query OK, 1 row affected (0.10 sec) mysql> insert into DemoTable values('David'); Query OK, 1 row affected (0.11 sec) mysql> insert into DemoTable values('Robert'); Query OK, 1 row affected (0.18 sec) mysql> insert into DemoTable values('David'); Query OK, 1 row affected (0.16 sec) mysql> insert into DemoTable values('Chris'); Query OK, 1 row affected (0.14 sec)
Display all records from the table using select statement −
mysql> select *from DemoTable;
Output
+--------------+ | EmployeeName | +--------------+ | Sam | | David | | David | | Chris | | Robert | | Chris | | Sam | | Sam | | David | | Robert | | David | | Chris | +--------------+ 12 rows in set (0.00 sec)
Following is the query to get the count of values and display the count in a new column ordered in descending order −
mysql> select EmployeeName,count(EmployeeName) as Total from DemoTable -> group by EmployeeName -> order by Total DESC;
Output
+--------------+-------+ | EmployeeName | Total | +--------------+-------+ | David | 4 | | Chris | 3 | | Sam | 3 | | Robert | 2 | +--------------+-------+ 4 rows in set (0.00 sec)
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