How to reverse an array list in Java



Problem Description

How to reverse an array list?

Solution

Following example reverses an array list by using Collections.reverse(ArrayList)method.

Open Compiler
import java.util.ArrayList; import java.util.Collections; public class Main { public static void main(String[] args) { ArrayList arrayList = new ArrayList(); arrayList.add("A"); arrayList.add("B"); arrayList.add("C"); arrayList.add("D"); arrayList.add("E"); System.out.println("Before Reverse Order: " + arrayList); Collections.reverse(arrayList); System.out.println("After Reverse Order: " + arrayList); } }

Result

The above code sample will produce the following result.

Before Reverse Order: [A, B, C, D, E]
After Reverse Order: [E, D, C, B, A]

Following example is another example of reverse of array.

Open Compiler
public class HelloWorld { public static void main(String[] args) { int[] numbers = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }; System.out.println("Array before reverse:"); for (int i = 0; i < numbers.length; i++) { System.out.print(numbers[i] + " "); } for (int i = 0; i < numbers.length / 2; i++) { int temp = numbers[i]; numbers[i] = numbers[numbers.length - 1 - i]; numbers[numbers.length - 1 - i] = temp; } System.out.println("\nArray after reverse:"); for (int i = 0; i < numbers.length; i++) { System.out.print(numbers[i] + " "); } } }

The above code sample will produce the following result.

Array before reverse:
1 2 3 4 5 6 7 8 9 10 
Array after reverse:
10 9 8 7 6 5 4 3 2 1 
java_arrays.htm
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