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Java log10() Method with Example
The java.lang.Math.log10(double a) returns the base 10 logarithm of a double value. Special cases −
If the argument is NaN or less than zero, then the result is NaN.
If the argument is positive infinity, then the result is positive infinity.
If the argument is positive zero or negative zero, then the result is negative infinity.
If the argument is equal to 10n for integer n, then the result is n.
Example
Following is an example to implement the log10() method in Java −
import java.lang.*; public class MathDemo { public static void main(String[] args) { double x = 56567.5; double y = 100; // get the base 10 logarithm for x System.out.println("Math.log10(" + x + ")=" + Math.log10(x)); // get the base 10 logarithm for y System.out.println("Math.log10(" + y + ")=" + Math.log10(y)); } }
Output
Math.log10(56567.5)=4.752566985524987 Math.log10(100.0)=2.0
Let us see another example −
Example
import java.lang.*; public class MathDemo { public static void main(String[] args) { double x = -30; double y = 1.0 / 0; ; // get the base 10 logarithm for x System.out.println("Math.log10(" + x + ")=" + Math.log10(x)); // get the base 10 logarithm for y System.out.println("Math.log10(" + y + ")=" + Math.log10(y)); } }
Output
Math.log10(-30.0)=NaN Math.log10(Infinity)=Infinity
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