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Java Integer compareTo Method
The java.lang.Integer.compareTo() method compares two Integer objects numerically. This method returns the value 0 if this Integer is equal to the argument Integer, a value less than 0 if this Integer is numerically less than the argument Integer and a value greater than 0 if this Integer is numerically greater than the argument Integer.
At first, set two Integer objects −
Integer obj1 = new Integer("100"); Integer obj2 = new Integer("200");
Now, compare those object −
int res = obj1.compareTo(obj2);
Following is an example to implement the compareTo() method in Java −
Example
public class Main { public static void main(String[] args) { Integer obj1 = new Integer("100"); Integer obj2 = new Integer("200"); int res = obj1.compareTo(obj2); if(retval > 0) { System.out.println("obj1 is greater than obj2"); } else if(retval < 0) { System.out.println("obj1 is less than obj2"); } else { System.out.println("obj1 is equal to obj2"); } } }
Output
obj1 is less than obj2
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