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Fetch Records with Odd Customer ID Using For Loop in JavaScript
Let’s say the following is our object −
var customerDetails= [ { customerId:101, customerName:"John" }, { customerId:102, customerName:"David" }, { customerId:103, customerName:"Mike" }, { customerId:104, customerName:"Bob" } ]
Use for loop with the following condition to display only odd CustomerID records −
for(var index=0;index<customerDetails.length;index++){ if(customerDetails[index].customerId % 2 !=0){ // } }
Example
var customerDetails= [ { customerId:101, customerName:"John" }, { customerId:102, customerName:"David" }, { customerId:103, customerName:"Mike" }, { customerId:104, customerName:"Bob" } ] for(var index=0;index<customerDetails.length;index++){ if(customerDetails[index].customerId % 2 !=0){ console.log("Customer Id="+customerDetails[index].customerId); console.log("Customer Name="+customerDetails[index].customerName); console.log("--------------------------------------------------- --------") } console.log(""); }
To run the above program, you need to use the following command −
node fileName.js.
Here, my file name is demo71.js.
Output
This will produce the following output −
PS C:\Users\Amit\JavaScript-code> node demo71.js Customer Id=101 Customer Name=John ----------------------------------------------------------- Customer Id=103 Customer Name=Mike -----------------------------------------------------------
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