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Find Minimum Element in Array Using Binary Search in C
C programming language provides two types of searching techniques. They are as follows −
Binary Search
- This method can be applied only to sorted list.
- The given list is divided into two equal parts.
- The given key is compared with the middle element of the list.
Here, three situations may occur, which are as follows −
-
If the middle element matches the key, then the search will end successfully here
-
If the middle element is greater than the key, then the search will proceed in the left partition.
-
If the middle element is lower than the key, then the search will proceed in the right partition.
Input
Unsorted list of elements, key.
Output
- Success – If key is found
- Unsuccessful – Otherwise
key = 20 mid = (low +high) /2
Program 1
Following is the C program to find the minimum element in an array by using binary search −
#include<stdio.h> int main(){ int a[50], n, i, key, flag = 0, low, mid, high; printf("enter the no: of elements:"); scanf ("%d",&n); printf("enter the elements:"); for(i=0; i<n; i++) scanf( "%d", &a[i]); printf("enter a key element:"); scanf ("%d", &key); low = 0; high = n-1; while (low<= high ){ mid = (low + high) /2; if (a[mid] == key){ flag = 1; break; } else{ if (a[mid] > key) high = mid-1; else low = mid+1; } } if (flag == 1) printf ("search is successful"); else printf("search is unsuccessful"); return 0; }
Output
When the above program is executed, it produces the following result −
Run 1: enter the no: of elements:5 enter the elements: 12 34 11 56 67 enter a key element:45 search is unsuccessful Run 2: enter the no: of elements:3 enter the elements: 12 34 56 enter a key element:34 search is successful
Program 2
Given below is another C program to find the minimum element in an array by using binary search −
#include<stdio.h> void Bmin(int *a, int i, int n){ int j, temp; temp = a[i]; j = 2 * i; while (j <= n){ if (j < n && a[j+1] > a[j]) j = j + 1; if (temp < a[j]) break; else if (temp >= a[j]){ a[j / 2] = a[j]; j = 2 * j; } } a[j/2] = temp; return; } int binarysearchmin(int *a,int n){ int i; for(i = n/2; i >= 1; i--){ Bmin(a,i,n); } return a[1]; } int main(){ int n, i, x, min; int a[20]; printf("Enter no of elements in an array
"); scanf("%d", &n); printf("
Enter %d elements: ", n); for (i = 1; i <= n; i++){ scanf("%d", &a[i]); } min = binarysearchmin(a, n); printf("\minimum element in an array is : %d", min); return 0; }
Output
When the above program is executed, it produces the following result −
Enter no of elements in an array 5 Enter 5 elements: 12 23 34 45 56 minimum element in an array is: 12