
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Find Maximum Power of a Number that Divides a Factorial in C++
Suppose we have two numbers n and fact. We have to find the largest power of n, that divides fact! (factorial of fact). So if fact = 5, and n = 2, then output will be 3. So 5! = 120, and this is divisible by 2^3 = 8.
Here we will use the Legendre’s formula. This finds largest power of a prime, that divides fact!. We will find all prime factors of n, then find largest power of it, that divides fact!.
So if fact is 146, and n = 15, then prime factors of n are 5 and 3. So
for 3, it will be [146/3] + [48/3] + [16/3] + [5/3] + [1/3] = 48 + 16 + 5 + 1 + 0 = 70.
for 5, it will be [146/5] + [29/5] + [5/5] + [1/3] = 29 + 5 + 1 + 0 = 35.
Example
#include<iostream> #include<cmath> using namespace std; int getPowerPrime(int fact, int p) { int res = 0; while (fact > 0) { res += fact / p; fact /= p; } return res; } int findMinPower(int fact, int n) { int res = INT_MAX; for (int i = 2; i <= sqrt(n); i++) { int cnt = 0; if (n % i == 0) { cnt++; n = n / i; } if (cnt > 0) { int curr = getPowerPrime(fact, i) / cnt; res = min(res, curr); } } if (n >= 2) { int curr = getPowerPrime(fact, n); res = min(res, curr); } return res; } int main() { int fact = 146, n = 5; cout << "Minimum power: " << findMinPower(fact, n); }
Output
Minimum power: 35
Advertisements