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Evaluation of Expression Tree in C++
In this problem, we are given an expression tree that consist of binary operations like +, - , /, *. We need to do the evaluation of the expression tree and then return the result.
Expression Tree is a special type of binary tree in which each node either consist of an operator or operand which are distributed as−
- Leaf nodes of the tree are values on which the operation is to be performed.
- Non-leaf nodes consist of the binary operator denoting the operation to be performed.
Let’s take an example to understand the problem,
Input:
Output: 1
Explanation:
Decoding the expression tree,
Exp = ( (5+9) / (2*7) )
= ( 14 / 14 )
= 1
Solution Approach:
A simple solution to the problem is by performing one operation each from root, for operends we will solve the subtree. As all operations are binary the nodes of a tree either have two childrens or none.
We will use recursion to solve each node's binary operation.
Program to illustrate the working of our solution,
Example
#include <bits/stdc++.h> using namespace std; class node { public: string value; node *left = NULL, *right = NULL; node(string x) { value = x; } }; int solveExpressionTree(node* root) { if (!root) return 0; if (!root->left && !root->right) return stoi(root->value); int leftSubTreeSol = solveExpressionTree(root->left); int rightSubTreeSol = solveExpressionTree(root->right); if (root->value == "+") return leftSubTreeSol + rightSubTreeSol; if (root->value == "-") return leftSubTreeSol - rightSubTreeSol; if (root->value == "*") return leftSubTreeSol * rightSubTreeSol; if (root -> value == "/") return leftSubTreeSol / rightSubTreeSol; return -1; } int main() { node *root = new node("/"); root->left = new node("+"); root->left->left = new node("9"); root->left->right = new node("5"); root->right = new node("*"); root->right->left = new node("2"); root->right->right = new node("7"); cout<<"The evaluation of expression tree is "<<solveExpressionTree(root); return 0; }
Output −
The evaluation of expression tree is 1
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