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Compute Cross Product of Two Vectors in C++
This is a C++ program to compute Cross Product of Two Vectors.
Let us suppose,
M = m1 * i + m2 * j + m3 * k
N = n1 * i + n2 * j + n3 * k.
So, cross product = (m2 * n3 – m3 * n2) * i + (m1 * n3 – m3 * n1) * j + (m1 * n1 – m2 * n1) * k
where m2 * n3 – m3 * n2, m1 * n3 – m3 * n1 and m1 * n1 – m2 * n1 are the coefficients of unit vector along i, j and k directions.
Algorithm
Begin Declare a function cProduct(). Declare three vectors v_A[], v_B[], c_P[] of the integer datatype. c_P[0] = v_A[1] * v_B[2] - v_A[2] * v_B[1]. c_P[1] = -(v_A[0] * v_B[2] - v_A[2] * v_B[0]). c_P[2] = v_A[0] * v_B[1] - v_A[1] * v_B[0]. Initialize values in v_A[] vector. Initialize values in v_B[] vector. Initialize c_P[] vector with an integer variable n. Print “Cross product:”. Call the function cProduct() to perform cross product within v_A[] and v_B[]. for (int i = 0; i < n; i++) print the value of c_P[] vector. End.
Example Code
#include #define n 3 using namespace std; void crossProduct(int v_A[], int v_B[], int c_P[]) { c_P[0] = v_A[1] * v_B[2] - v_A[2] * v_B[1]; c_P[1] = -(v_A[0] * v_B[2] - v_A[2] * v_B[0]); c_P[2] = v_A[0] * v_B[1] - v_A[1] * v_B[0]; } int main() { int v_A[] = { 7, 6, 4 }; int v_B[] = { 2, 1, 3 }; int c_P[n]; cout << "Cross product:"; crossProduct(v_A, v_B, c_P); for (int i = 0; i < n; i++) cout << c_P[i] << " "; return 0; }
Output
Cross product: 14 13 -5
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