• Category A : If HP is in the form (4n + 1)

  • Category B : If HP is in the f">

    C++ code to find how many upgrade to make HP greater than current



    Suppose we have a number n. In a game, every character has four different health points (HP). The categories are as follows −

    • Category A : If HP is in the form (4n + 1)

    • Category B : If HP is in the form (4n + 3)

    • Category C : If HP is in the form (4n + 2)

    • Category D : If HP is in the form 4n

    These 4 categories ordered from highest to lowest as A > B > C > D. So, category A is the highest and category D is the lowest. While playing the game, players can increase the HP of the character. Now, Amal wants you to increase his HP by at most 2 (that is, either by 0, 1 or 2). We have to find how much should he increase his HP so that it has the highest possible category?

    So, if the input is like n = 98, then the output will be 1 B, because 98 is in category C as (4*24 + 2), by increasing it by 1, it will be upgraded to category B, but if we increase it to 2, it will be 100 (4*25) which is category D. So at max category B is possible.

    Steps

    To solve this, we will follow these steps −

    if n mod 4 is same as 2, then:
       return "1 B"
    Otherwise
       return |(n mod 4) - 1| and 'A'

    Example

    Let us see the following implementation to get better understanding −

    #include <bits/stdc++.h>
    using namespace std;
    void solve(int n){
       if (n % 4 == 2)
          cout << "1 B";
       else
          cout << abs(n % 4 - 1) << " A";
    }
    int main(){
       int n = 98;
       solve(n);
    }

    Input

    98

    Output

    1 B
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