C++ code to check array can be formed from Equal Not-Equal sequence or not



Suppose we have a string S of length . Consider there are n numbers and they are arranged in a circle. We do not know the values of these numbers but if S[i] = 'E' it indicates ith and (i+1)th numbers are same, but if that is 'N' then they are different. From S we have to check whether we can recreate the sequence or not.

So, if the input is like S = "ENNEENE", then the output will be True, because we can assign values like [15,15,4,20,20,20,15].

Steps

To solve this, we will follow these steps −

if S has single 'N', then: return false return true

Example

Let us see the following implementation to get better understanding −

Open Compiler
#include<bits/stdc++.h> using namespace std; bool solve(string S){ if (count(S.begin(), S.end(), 'N') == 1) return false; return true; } int main(){ string S = "ENNEENE"; cout << solve(S) << endl; }

Input

"ENNEENE"

Output

1
Updated on: 2022-03-11T07:02:20+05:30

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