Check Elementwise if Intervals in IntervalIndex Contain Value in Python Pandas

To return an IntervalArray identical to the current one but closed on the specified side, use the set_closed() method with parameter set as both.

At first, import the required libraries −

import pandas as pd

Create IntervalArray −

index = pd.arrays.IntervalArray.from_breaks(range(6))

Display the interval −

print("IntervalIndex...\n",index)

Return an IntervalArray identical to the current one but closed on specified side i.e. "both" here −

print("\nResult...",index.set_closed('both'))

Example

Following is the code −

import pandas as pd

# Create IntervalArray
index = pd.arrays.IntervalArray.from_breaks(range(6))

# Display the interval
print("IntervalIndex...\n",index)

# Display the interval length
print("\nIntervalIndex length...\n",index.length)

# the left bound
print("\nThe left bound for the IntervalIndex...\n",index.left)

# the right bound
print("\nThe right bound for the IntervalIndex...\n",index.right)

# Return an IntervalArray identical to the current one but closed on specified
# side i.e. "both" here
print("\nResult...",index.set_closed('both'))

Output

This will produce the following output −

IntervalIndex...
<IntervalArray>
[(0, 1], (1, 2], (2, 3], (3, 4], (4, 5]]
Length: 5, dtype: interval[int64, right]

IntervalIndex length...
Int64Index([1, 1, 1, 1, 1], dtype='int64')

The left bound for the IntervalIndex...
Int64Index([0, 1, 2, 3, 4], dtype='int64')

The right bound for the IntervalIndex...
Int64Index([1, 2, 3, 4, 5], dtype='int64')

Result... <IntervalArray>
[[0, 1], [1, 2], [2, 3], [3, 4], [4, 5]]
Length: 5, dtype: interval[int64, both]