C# Program to Skip Specified Number of Elements in an Array

The following is our array −

int[] points = { 210, 250, 300, 350, 420};

Use skip() method to skip elements. Add the number as an argument that displays the number of elements to be returned.

IEnumerable<int> skipEle = points.AsQueryable().OrderByDescending(s => s).Skip(3);

Example

 Live Demo

using System;
using System.Linq;
using System.Collections.Generic;
public class Demo {
   public static void Main() {
      int[] points = { 210, 250, 300, 350, 420};
      Console.WriteLine("Initial array...");
   
      foreach (int res in points)
      Console.WriteLine(res);
      IEnumerable<int> skipEle = points.AsQueryable().OrderByDescending(s => s).Skip(3);
      Console.WriteLine("Skipped 3 elements...");

      foreach (int res in skipEle)
      Console.WriteLine(res);
   }
}

Output

Initial array...
210
250
300
350
420
Skipped 3 elements...
250
210