Find Sum of Digits of 8-Bit Number in 8085

In this program we will see how to add the digits of an 8-bit number.

Problem Statement

Write 8085 Assembly language program to add the digits of an 8-bit number stored in memory location 8000H.

Discussion

To get the digits of an 8-bit number, we can use the masking operation. At first we will mask the upper nibble, and then the lower nibble. After masking the lower nibble, we have to rotate it to the right to make it least significant nibble. Then we can simply add it to the stored nibble to get the sum.

Input

Address
 Data
...
 ...
8000
 8A
...
 ...

Program

Address
 HEX Codes
 Mnemonics
 Comments
F000
 3A, 00, 80
 LDA 8000H
 Load the number into A
F003
 4F
 MOV C, A
 Copy the number to C
F004
 E6, 0F
 ANI 0FH
 Take the lower nibble
F006
 47
 MOV B, A
 Store the result into B
F007
 79
 MOV A, C
 Restore the actual number
F008
 E6, F0
 ANI F0
 Take the upper nibble
F00A
 0F
 RRC
 Rotate the bits four times
F00B
 0F
 RRC


F00C
 0F
 RRC


F00D
 0F
 RRC


F00E
 80
 ADD B
 Add A with B
F00F
 32, 50, 80
 STA 8050H
 Store the result at 8050H
F012
 76
 HLT
 Terminate the program


Output

Address
 Data
...
 ...
8050
 12
...
 ...
Updated on: 2020-06-30T05:01:51+05:30

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