Convert 8-Bit Binary to BCD in 8085

In this program we will see how to convert binary numbers to its BCD equivalent.

Problem Statement

A binary number is store dat location 800H. Convert the number into its BCD equivalent and store it to the memory location 8050H.

Discussion

Here we are taking a number from the memory, and initializing it as a counter. Now in each step of this counter we are incrementing the number by 1, and adjust the decimal value. By this process we are finding the BCD value of binary number or hexadecimal number.

We can use INR instruction to increment the counter in this case but this instruction will not affect carry flag, so for that reason we have used ADI 10H

Input

Address Data
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 .
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8000 34
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.
 .
.
.

Flow Diagram

Program

Address HEX Codes Labels Mnemonics Comments
F000 21, 00, 80
LXI H,8000H Initialize memory pointer
F003 16, 00
MVI D,00H Clear D- reg for Most significant Byte
F005 AF
XRA A Clear Accumulator
F006 4E
MOV C, M Get HEX data
F007  C6, 01 LOOP ADI 01H Count the number one by one
F009  27
DAA Adjust for BCD count
F00A D2, 0E, F0
JNC SKIP Jump to SKIP
F00D  14
INR D Increase D
F00E 0D SKIP DCR C Decrease C register
F00F C2, 07, F0
JNZ LOOP Jump to LOOP
F012 6F
MOV L, A Load the Least Significant Byte
F013 62
MOV H, D Load the Most Significant Byte
F014 22, 50, 80
SHLD 8050H Store the BCD
F017 76 
HLT Terminate the program


Output

Address Data
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.
.
 .
.
.
8050 52
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.
.
 .
.
.
Updated on: 2019-07-30T22:30:24+05:30

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