3 and 7 in Python

Suppose we have a positive number n, we have to find that we can make n by summing up some non-negative multiple of 3 and some non-negative multiple of 7 or not.

So, if the input is like 13, then the output will be True, as 13 can be written as 1*7+2*3 = 13

To solve this, we will follow these steps −

• for i in range 0 to n+1, increase by 7, do

  • if n-i is divisible by 3, then

    • return True

• return False

Let us see the following implementation to get better understanding −

Example

 Live Demo

class Solution:
   def solve(self, n):
      for i in range(0,n+1,7):
         if (n-i)%3 == 0:
            return True
      return False
ob = Solution()
print(ob.solve(13))

Input

13

Output

True