Sum of consecutive two elements in a array

Last Updated : 20 Feb, 2023

Given an array print sum of the pairwise consecutive elements.

Examples:

Input  : 8, 5, 4, 3, 15, 20
Output : 13, 9, 7, 18, 35

Input  : 5, 10, 15, 20
Output : 15, 25, 35

The solution is to traverse the array and saving the sum of consecutive numbers in the variable sum.

Implementation:

C++

// C++ program to print the  
// sum of the consecutive elements. 
#include <stdio.h> 
#include <stdlib.h> 
  
// Function to print pairwise sum 
void pairwiseSum(int arr[], int n)  
{ 
    int sum = 0;    
    for (int i = 0; i < n - 1; i++)  
    { 
        // adding the alternate numbers 
        sum = arr[i] + arr[i + 1]; 
        printf(" %d ", sum); 
    } 
} 
  
// Driver function to test function 
int main() 
{ 
    int arr[] = {4, 10, 15, 5, 6}; 
    int n = sizeof(arr) / sizeof(arr[0]); 
      
    pairwiseSum(arr, n); 
    return 0; 
} 

Java

// Java program to print the  
// sum of the consecutive elements. 
  
class Arraysum { 
      
    // Function to print Alternatesum 
    static void pairwiseSum(int arr[], int n) 
    { 
        int sum = 0; 
        for (int i = 0; i + 1 < n; i++)  
        { 
            // adding the alternate numbers 
            sum = arr[i] + arr[i + 1]; 
            System.out.print(sum + " "); 
        } 
    } 
      
    /*driver function to test function*/
    public static void main(String[] args) 
    { 
      
        int arr[] = {4, 10, 15, 5, 6}; 
        int n = arr.length; 
        pairwiseSum(arr, n); 
    } 
} 

Python3

# Python3 program to print the  
# sum of the consecutive elements. 
  
# Function to print alternate sum 
def pairwiseSum(lst, n): 
    sum = 0; 
    for i in range(len(lst)-1): 
          
        # adding the alternate numbers 
        sum = lst[i] + lst[i + 1] 
        print (sum, end = " ") 
      
# driver function to test function 
arr =[4, 10, 15, 5, 6] 
size = len(arr) 
pairwiseSum(arr, size) 

C#

// C# program to print the  
// sum of the consecutive elements. 
using System; 
  
class Arraysum { 
      
    // Function to print Alternatesum 
    static void pairwiseSum(int []arr, int n) 
    { 
        int sum = 0; 
        for (int i = 0; i + 1 < n; i++)  
        { 
            // adding the alternate numbers 
            sum = arr[i] + arr[i + 1]; 
            Console.Write(sum + " "); 
        } 
    } 
      
    // Driver function  
    public static void Main() 
    { 
      
        int []arr = {4, 10, 15, 5, 6}; 
        int n = arr.Length; 
        pairwiseSum(arr, n); 
    } 
} 
  
// This code is contributed by vt_m. 

PHP

<?php 
// PHP program to print the  
// sum of the consecutive elements. 
  
// Function to print pairwise sum 
function pairwiseSum($arr, $n)  
{ 
    $sum = 0;  
    for ($i = 0; $i < $n - 1; $i++)  
    { 
          
        // adding the alternate numbers 
        $sum = $arr[$i] + $arr[$i + 1]; 
        echo $sum," "; 
    } 
} 
  
    // Driver Code 
    $arr = array (4, 10, 15, 5, 6); 
    $n = sizeof($arr) ; 
    pairwiseSum($arr, $n); 
      
// This code is contributed by ajit 
?> 

Javascript

<script> 
  
// Javascript program to print the  
// sum of the consecutive elements. 
  
// Function to print Alternatesum 
function pairwiseSum(arr, n) 
{ 
    let sum = 0; 
    for(let i = 0; i + 1 < n; i++)  
    { 
          
        // Adding the alternate numbers 
        sum = arr[i] + arr[i + 1]; 
        document.write(sum + " "); 
    } 
} 
  
// Driver code 
let arr = [ 4, 10, 15, 5, 6 ]; 
let n = arr.length; 
  
pairwiseSum(arr, n); 
  
// This code is contributed by divyesh072019 
  
</script>

Output

 14  25  20  11

Time Complexity: O(n) where n is no of elements in given array

Auxiliary Space: O(1) because it is using constant space for variables

Sum of minimum difference between consecutive elements of an array

pranav gupta 8

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Sum of consecutive two elements in a array

C++

Java

Python3

C#

PHP

Javascript

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