Replace Linked List nodes with its closest Tribonacci number
Last Updated :
23 Jul, 2025
Given a singly linked list of integers, the task is to replace every node with its closest Tribonacci number and return the modified linked list.
Examples:
Input: List: 3 -> 5 -> 9 -> 12
Output: 2 -> 4 -> 7 -> 13
Explanation: The closest Tribonacci numbers for each node are:
- Node 1 (value = 3): Closest Tribonacci number = 2.
- Node 2 (value = 5): Closest Tribonacci number = 4.
- Node 3 (value = 9): Closest Tribonacci number = 7.
- Node 4 (value = 12): Closest Tribonacci number = 13.
Input: List: 2->8->14->5->16
Output: 2->7->13->4->13
Explanation: The closest Tribonacci numbers for each node are:
- Node 1 (value = 2): Closest Tribonacci number = 2.
- Node 2 (value = 8): Closest Tribonacci number = 7.
- Node 3 (value = 14): Closest Tribonacci number = 13.
- Node 4 (value = 5): Closest Tribonacci number = 4.
- Node 5 (value = 16): Closest Tribonacci number = 13.
Approach: This can be solved with the following idea:
- The problem requires us to replace every node in a singly linked list with its closest Tribonacci number. A Tribonacci sequence is a sequence of numbers where each number is the sum of the three preceding numbers, starting with 0, 1, 1. For example, the first few terms of the Tribonacci sequence are: 0, 1, 1, 2, 4, 7, 13, 24, 44, 81, ...
- To solve this problem, we can iterate through the linked list and replace each node's value with its closest Tribonacci number. We can compute the closest Tribonacci number for a given value by generating the Tribonacci sequence up to the point where the largest Tribonacci number is greater than the given value. Then, we can iterate through the sequence to find the Tribonacci number with the smallest absolute difference from the given value.
Here's the step-by-step approach:
- Define a helper function closest_tribonacci(num) that takes an integer num as input and returns the closest Tribonacci number to num.
- Inside the closest_tribonacci function, generate the Tribonacci sequence up to the point where the largest Tribonacci number is greater than num. We can do this by initializing a vector tribonacci with the first three Tribonacci numbers, then appending the sum of the last three numbers to the vector until the last element is greater than num.
- Initialize two variables min_diff and closest_trib to the difference between num and the first Tribonacci number in the sequence and the first Tribonacci number, respectively.
- Iterate through the rest of the Fibonacci sequence and for each element, compute the absolute difference between it and num. If the difference is smaller than min_diff, update min_diff and closest_trib to the new values.
- Return closest_trib from the closest_tribonacci function.
- Define a function replaceWithClosestTribonacci(head) that takes the head node of a singly linked list as input and modifies the linked list by replacing each node's value with its closest Tribonacci number. Iterate through the linked list and for each node, call the closest_tribonacci function to get its closest Tribonacci number, and replace the node's value with this number.
- Return the head node of the modified linked list.
Below is the implementation of the above approach:
C++
// C++ code for the above approach:
#include <bits/stdc++.h>
using namespace std;
// Define the linked list node
struct Node {
int val;
Node* next;
Node(int x)
: val(x), next(nullptr)
{
}
};
// Helper function to compute the closest
// Tribonacci number
int closest_tribonacci(int num)
{
vector<int> tribonacci = { 0, 1, 1 };
while (tribonacci.back() < num) {
int next_trib = tribonacci[tribonacci.size() - 1]
+ tribonacci[tribonacci.size() - 2]
+ tribonacci[tribonacci.size() - 3];
tribonacci.push_back(next_trib);
}
int min_diff = abs(num - tribonacci[0]);
int closest_trib = tribonacci[0];
for (int i = 1; i < tribonacci.size(); i++) {
int diff = abs(num - tribonacci[i]);
if (diff < min_diff) {
min_diff = diff;
closest_trib = tribonacci[i];
}
}
return closest_trib;
}
// Function to replace linked list nodes
// with closest Tribonacci numbers
Node* replaceWithClosestTribonacci(Node* head)
{
Node* curr = head;
while (curr != nullptr) {
int closest_trib = closest_tribonacci(curr->val);
curr->val = closest_trib;
curr = curr->next;
}
return head;
}
// Function to print list
void printList(Node* head)
{
Node* curr = head;
while (curr != nullptr) {
cout << curr->val << "->";
curr = curr->next;
}
cout << "null" << endl;
}
// Driver code
int main()
{
Node* head = new Node(2);
head->next = new Node(8);
head->next->next = new Node(14);
head->next->next->next = new Node(5);
head->next->next->next->next = new Node(16);
// Function call
replaceWithClosestTribonacci(head);
printList(head);
return 0;
}
//Java code for the above approach:
import java.util.ArrayList;
import java.util.List;
// Define the linked list node
class Node {
int val;
Node next;
Node(int x) {
val = x;
next = null;
}
}
public class GFG {
// Helper function to compute the closest Tribonacci number
public static int closestTribonacci(int num) {
List<Integer> tribonacci = new ArrayList<>();
tribonacci.add(0);
tribonacci.add(1);
tribonacci.add(1);
while (tribonacci.get(tribonacci.size() - 1) < num) {
int nextTrib = tribonacci.get(tribonacci.size() - 1)
+ tribonacci.get(tribonacci.size() - 2)
+ tribonacci.get(tribonacci.size() - 3);
tribonacci.add(nextTrib);
}
int minDiff = Math.abs(num - tribonacci.get(0));
int closestTrib = tribonacci.get(0);
for (int i = 1; i < tribonacci.size(); i++) {
int diff = Math.abs(num - tribonacci.get(i));
if (diff < minDiff) {
minDiff = diff;
closestTrib = tribonacci.get(i);
}
}
return closestTrib;
}
// Function to replace linked list nodes with closest Tribonacci numbers
public static Node replaceWithClosestTribonacci(Node head) {
Node curr = head;
while (curr != null) {
int closestTrib = closestTribonacci(curr.val);
curr.val = closestTrib;
curr = curr.next;
}
return head;
}
// Function to print list
public static void printList(Node head) {
Node curr = head;
while (curr != null) {
System.out.print(curr.val + "->");
curr = curr.next;
}
System.out.println("null");
}
// Driver code
public static void main(String[] args) {
Node head = new Node(2);
head.next = new Node(8);
head.next.next = new Node(14);
head.next.next.next = new Node(5);
head.next.next.next.next = new Node(16);
// Function call to replace values with closest Tribonacci numbers
replaceWithClosestTribonacci(head);
// Print the modified linked list
printList(head);
}
}
#Python code for the above approach:
class Node:
def __init__(self, x):
self.val = x
self.next = None
def closest_tribonacci(num):
# Compute the closest Tribonacci number to the given num
tribonacci = [0, 1, 1]
while tribonacci[-1] < num:
next_trib = tribonacci[-1] + tribonacci[-2] + tribonacci[-3]
tribonacci.append(next_trib)
min_diff = abs(num - tribonacci[0])
closest_trib = tribonacci[0]
for i in range(1, len(tribonacci)):
diff = abs(num - tribonacci[i])
if diff < min_diff:
min_diff = diff
closest_trib = tribonacci[i]
return closest_trib
def replaceWithClosestTribonacci(head):
# Replace the values in the linked list with the closest Tribonacci numbers
curr = head
while curr:
closest_trib = closest_tribonacci(curr.val)
curr.val = closest_trib
curr = curr.next
return head
def printList(head):
# Print the linked list
curr = head
while curr:
print(curr.val, "->", end=" ")
curr = curr.next
print("null")
# Driver code
if __name__ == "__main__":
head = Node(2)
head.next = Node(8)
head.next.next = Node(14)
head.next.next.next = Node(5)
head.next.next.next.next = Node(16)
# Function call to replace values with closest Tribonacci numbers
replaceWithClosestTribonacci(head)
# Print the modified linked list
printList(head)
// C# code for the above approach:
using System;
using System.Collections.Generic;
// Define the linked list node
class Node
{
public int val;
public Node next;
public Node(int x)
{
val = x;
next = null;
}
}
class Program
{
// Helper function to compute the closest Tribonacci number
static int ClosestTribonacci(int num)
{
List<int> tribonacci = new List<int>() { 0, 1, 1 };
while (tribonacci[tribonacci.Count - 1] < num)
{
int nextTrib = tribonacci[tribonacci.Count - 1] +
tribonacci[tribonacci.Count - 2] +
tribonacci[tribonacci.Count - 3];
tribonacci.Add(nextTrib);
}
int minDiff = Math.Abs(num - tribonacci[0]);
int closestTrib = tribonacci[0];
for (int i = 1; i < tribonacci.Count; i++)
{
int diff = Math.Abs(num - tribonacci[i]);
if (diff < minDiff)
{
minDiff = diff;
closestTrib = tribonacci[i];
}
}
return closestTrib;
}
// Function to replace linked list nodes with closest
// Tribonacci numbers
static Node ReplaceWithClosestTribonacci(Node head)
{
Node curr = head;
while (curr != null)
{
int closestTrib = ClosestTribonacci(curr.val);
curr.val = closestTrib;
curr = curr.next;
}
return head;
}
// Function to print list
static void PrintList(Node head)
{
Node curr = head;
while (curr != null)
{
Console.Write(curr.val + "->");
curr = curr.next;
}
Console.WriteLine("null");
}
// Driver code
static void Main()
{
Node head = new Node(2);
head.next = new Node(8);
head.next.next = new Node(14);
head.next.next.next = new Node(5);
head.next.next.next.next = new Node(16);
// Function call
ReplaceWithClosestTribonacci(head);
PrintList(head);
}
}
class Node {
constructor(x) {
this.val = x;
this.next = null;
}
}
function closestTribonacci(num) {
const tribonacci = [0, 1, 1];
while (tribonacci[tribonacci.length - 1] < num) {
const nextTrib = tribonacci[tribonacci.length - 1]
+ tribonacci[tribonacci.length - 2]
+ tribonacci[tribonacci.length - 3];
tribonacci.push(nextTrib);
}
let minDiff = Math.abs(num - tribonacci[0]);
let closestTrib = tribonacci[0];
for (let i = 1; i < tribonacci.length; i++) {
const diff = Math.abs(num - tribonacci[i]);
if (diff < minDiff) {
minDiff = diff;
closestTrib = tribonacci[i];
}
}
return closestTrib;
}
function replaceWithClosestTribonacci(head) {
let curr = head;
while (curr !== null) {
const closestTrib = closestTribonacci(curr.val);
curr.val = closestTrib;
curr = curr.next;
}
return head;
}
function printList(head) {
let curr = head;
while (curr !== null) {
process.stdout.write(curr.val + "->");
curr = curr.next;
}
console.log("null");
}
// Driver code
const head = new Node(2);
head.next = new Node(8);
head.next.next = new Node(14);
head.next.next.next = new Node(5);
head.next.next.next.next = new Node(16);
// Function call to replace values with closest Tribonacci numbers
replaceWithClosestTribonacci(head);
// Print the modified linked list
printList(head);
Output2->7->13->4->13->null
Time Complexity: O(n * log(num))
Auxiliary Space: O(1)
Approach 2:
Approach: This can be solved with the following idea:
In this approach, we generate the Tribonacci numbers separately and then find the closest Tribonacci number for each node's value.
Here's the step-by-step approach:
- Create a helper function generateTribonacciNumbers(limit) that generates the Tribonacci numbers up to the given limit and returns them as a vector.
- Traverse the linked list and store the values in a vector values.
- Find the maximum value max_val in the values vector.
- Generate the Tribonacci numbers up to max_val using the helper function.
- Traverse the linked list again and replace each node's value with its closest Tribonacci number.
- For each node's value val, iterate through the Tribonacci numbers and find the closest number to val.
- Update the node's value with the closest Tribonacci number.
- Return the head of the modified linked list.
Below is the implementation of the above approach:
C++
#include<bits/stdc++.h>
using namespace std;
// Define the linked list node
struct Node {
int val;
Node* next;
Node(int x)
: val(x)
, next(nullptr)
{
}
};
// Helper function to generate Tribonacci numbers
vector<int> generateTribonacciNumbers(int limit)
{
vector<int> tribonacci = { 0, 1, 1 };
int i = 3;
while (tribonacci[i - 1] <= limit) {
tribonacci.push_back(tribonacci[i - 1]
+ tribonacci[i - 2]
+ tribonacci[i - 3]);
i++;
}
return tribonacci;
}
// Function to replace linked list nodes with closest
// Tribonacci numbers
Node* replaceWithClosestTribonacci(Node* head)
{
// Store the values in a vector
vector<int> values;
Node* curr = head;
while (curr != nullptr) {
values.push_back(curr->val);
curr = curr->next;
}
// Find the maximum value in the vector
int max_val
= *max_element(values.begin(), values.end());
// Generate Tribonacci numbers up to max_val
vector<int> tribonacci
= generateTribonacciNumbers(max_val);
// Replace node values with closest Tribonacci numbers
curr = head;
int n = tribonacci.size();
for (int val : values) {
int diff = INT_MAX;
int closest_trib = 0;
for (int i = 0; i < n; i++) {
if (abs(val - tribonacci[i]) < diff) {
diff = abs(val - tribonacci[i]);
closest_trib = tribonacci[i];
}
}
curr->val = closest_trib;
curr = curr->next;
}
return head;
}
// Function to print list
void printList(Node* head)
{
Node* curr = head;
while (curr != nullptr) {
cout << curr->val << "->";
curr = curr->next;
}
cout << "null" << endl;
}
// Driver code
int main()
{
Node* head = new Node(2);
head->next = new Node(8);
head->next->next = new Node(14);
head->next->next->next = new Node(5);
head->next->next->next->next = new Node(16);
// Function call
replaceWithClosestTribonacci(head);
printList(head);
return 0;
}
import java.util.ArrayList;
import java.util.List;
// Define the linked list node
class Node {
int val;
Node next;
public Node(int x) {
val = x;
next = null;
}
}
public class Main {
// Helper function to generate Tribonacci numbers
public static List<Integer> generateTribonacciNumbers(int limit) {
List<Integer> tribonacci = new ArrayList<>();
tribonacci.add(0);
tribonacci.add(1);
tribonacci.add(1);
int i = 3;
while (tribonacci.get(i - 1) <= limit) {
tribonacci.add(tribonacci.get(i - 1) + tribonacci.get(i - 2) + tribonacci.get(i - 3));
i++;
}
return tribonacci;
}
// Function to replace linked list nodes with closest Tribonacci numbers
public static Node replaceWithClosestTribonacci(Node head) {
// Store the values in a list
List<Integer> values = new ArrayList<>();
Node curr = head;
while (curr != null) {
values.add(curr.val);
curr = curr.next;
}
// Find the maximum value in the list
int maxVal = values.stream().mapToInt(Integer::intValue).max().orElse(0);
// Generate Tribonacci numbers up to maxVal
List<Integer> tribonacci = generateTribonacciNumbers(maxVal);
// Replace node values with closest Tribonacci numbers
curr = head;
int n = tribonacci.size();
for (int val : values) {
int diff = Integer.MAX_VALUE;
int closestTrib = 0;
for (int i = 0; i < n; i++) {
if (Math.abs(val - tribonacci.get(i)) < diff) {
diff = Math.abs(val - tribonacci.get(i));
closestTrib = tribonacci.get(i);
}
}
curr.val = closestTrib;
curr = curr.next;
}
return head;
}
// Function to print the list
public static void printList(Node head) {
Node curr = head;
while (curr != null) {
System.out.print(curr.val + "->");
curr = curr.next;
}
System.out.println("null");
}
// Driver code
public static void main(String[] args) {
Node head = new Node(2);
head.next = new Node(8);
head.next.next = new Node(14);
head.next.next.next = new Node(5);
head.next.next.next.next = new Node(16);
// Function call
replaceWithClosestTribonacci(head);
printList(head);
}
}
# Define the linked list node
class Node:
def __init__(self, x):
self.val = x
self.next = None
# Helper function to generate Tribonacci numbers
def generateTribonacciNumbers(limit):
tribonacci = [0, 1, 1]
i = 3
while tribonacci[i - 1] <= limit:
tribonacci.append(tribonacci[i - 1] + tribonacci[i - 2] + tribonacci[i - 3])
i += 1
return tribonacci
# Function to replace linked list nodes with closest
# Tribonacci numbers
def replaceWithClosestTribonacci(head):
# Store the values
values = []
curr = head
while curr != None:
values.append(curr.val)
curr = curr.next
# Find the maximum value in the vector
max_val = max(values)
# Generate Tribonacci numbers up to max_val
tribonacci = generateTribonacciNumbers(max_val)
# Replace node values with closest Tribonacci numbers
curr = head
n = len(tribonacci)
for val in values:
diff = float('inf')
closest_trib = 0
for i in range(n):
if abs(val - tribonacci[i]) < diff:
diff = abs(val - tribonacci[i])
closest_trib = tribonacci[i]
curr.val = closest_trib
curr = curr.next
return head
# Function to print list
def printList(head):
curr = head
while curr != None:
print(curr.val, "->", end="")
curr = curr.next
print("null")
# Driver code
head = Node(2)
head.next = Node(8)
head.next.next = Node(14)
head.next.next.next = Node(5)
head.next.next.next.next = Node(16)
replaceWithClosestTribonacci(head)
printList(head)
using System;
using System.Collections.Generic;
using System.Linq;
// Define the linked list node
public class Node
{
public int val;
public Node next;
public Node(int x)
{
val = x;
next = null;
}
}
class Program
{
// Helper function to generate Tribonacci numbers
public static List<int> GenerateTribonacciNumbers(int limit)
{
List<int> tribonacci = new List<int> { 0, 1, 1 };
int i = 3;
while (tribonacci[i - 1] <= limit)
{
tribonacci.Add(tribonacci[i - 1] + tribonacci[i - 2] + tribonacci[i - 3]);
i++;
}
return tribonacci;
}
// Function to replace linked list nodes with the closest Tribonacci numbers
public static Node ReplaceWithClosestTribonacci(Node head)
{
// Store the values in a list
List<int> values = new List<int>();
Node curr = head;
while (curr != null)
{
values.Add(curr.val);
curr = curr.next;
}
// Find the maximum value in the list
int max_val = values.Max();
// Generate Tribonacci numbers up to max_val
List<int> tribonacci = GenerateTribonacciNumbers(max_val);
// Replace node values with the closest Tribonacci numbers
curr = head;
int n = tribonacci.Count;
foreach (int val in values)
{
int diff = int.MaxValue;
int closest_trib = 0;
for (int i = 0; i < n; i++)
{
if (Math.Abs(val - tribonacci[i]) < diff)
{
diff = Math.Abs(val - tribonacci[i]);
closest_trib = tribonacci[i];
}
}
curr.val = closest_trib;
curr = curr.next;
}
return head;
}
// Function to print the list
public static void PrintList(Node head)
{
Node curr = head;
while (curr != null)
{
Console.Write(curr.val + "->");
curr = curr.next;
}
Console.WriteLine("null");
}
static void Main(string[] args)
{
Node head = new Node(2);
head.next = new Node(8);
head.next.next = new Node(14);
head.next.next.next = new Node(5);
head.next.next.next.next = new Node(16);
// Function call
ReplaceWithClosestTribonacci(head);
PrintList(head);
}
}
<script>
// JavaScript code for the above approach
// Define the linked list node
class Node {
constructor(val) {
this.val = val;
this.next = null;
}
}
// Helper function to generate Tribonacci numbers
function generateTribonacciNumbers(limit) {
let tribonacci = [0, 1, 1];
let i = 3;
while (tribonacci[i - 1] <= limit) {
tribonacci.push(tribonacci[i - 1] + tribonacci[i - 2] + tribonacci[i - 3]);
i++;
}
return tribonacci;
}
// Function to replace linked list nodes with closest Tribonacci numbers
function replaceWithClosestTribonacci(head) {
// Store the values in an array
let values = [];
let curr = head;
while (curr !== null) {
values.push(curr.val);
curr = curr.next;
}
// Find the maximum value in the array
let max_val = Math.max(...values);
// Generate Tribonacci numbers up to max_val
let tribonacci = generateTribonacciNumbers(max_val);
// Replace node values with closest Tribonacci numbers
curr = head;
let n = tribonacci.length;
for (let val of values) {
let diff = Number.MAX_SAFE_INTEGER;
let closest_trib = 0;
for (let i = 0; i < n; i++) {
if (Math.abs(val - tribonacci[i]) < diff) {
diff = Math.abs(val - tribonacci[i]);
closest_trib = tribonacci[i];
}
}
curr.val = closest_trib;
curr = curr.next;
}
return head;
}
// Function to print list
function printList(head) {
let curr = head;
while (curr !== null) {
document.write(curr.val + "->");
curr = curr.next;
}
document.write("null");
}
// Driver code
let head = new Node(2);
head.next = new Node(8);
head.next.next = new Node(14);
head.next.next.next = new Node(5);
head.next.next.next.next = new Node(16);
// Function call
replaceWithClosestTribonacci(head);
printList(head);
// This code is contributed by Susobhan Akhuli
</script>
Output2->7->13->4->13->null
Time Complexity: O(limit + n)
Auxiliary Space: O(limit + n)
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Trie Data StructureThe Trie data structure is a tree-like structure used for storing a dynamic set of strings. It allows for efficient retrieval and storage of keys, making it highly effective in handling large datasets. Trie supports operations such as insertion, search, deletion of keys, and prefix searches. In this
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Algorithms
Searching AlgorithmsSearching algorithms are essential tools in computer science used to locate specific items within a collection of data. In this tutorial, we are mainly going to focus upon searching in an array. When we search an item in an array, there are two most common algorithms used based on the type of input
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Sorting AlgorithmsA Sorting Algorithm is used to rearrange a given array or list of elements in an order. For example, a given array [10, 20, 5, 2] becomes [2, 5, 10, 20] after sorting in increasing order and becomes [20, 10, 5, 2] after sorting in decreasing order. There exist different sorting algorithms for differ
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Introduction to RecursionThe process in which a function calls itself directly or indirectly is called recursion and the corresponding function is called a recursive function. A recursive algorithm takes one step toward solution and then recursively call itself to further move. The algorithm stops once we reach the solution
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Greedy AlgorithmsGreedy algorithms are a class of algorithms that make locally optimal choices at each step with the hope of finding a global optimum solution. At every step of the algorithm, we make a choice that looks the best at the moment. To make the choice, we sometimes sort the array so that we can always get
3 min read
Graph AlgorithmsGraph is a non-linear data structure like tree data structure. The limitation of tree is, it can only represent hierarchical data. For situations where nodes or vertices are randomly connected with each other other, we use Graph. Example situations where we use graph data structure are, a social net
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Dynamic Programming or DPDynamic Programming is an algorithmic technique with the following properties.It is mainly an optimization over plain recursion. Wherever we see a recursive solution that has repeated calls for the same inputs, we can optimize it using Dynamic Programming. The idea is to simply store the results of
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Bitwise AlgorithmsBitwise algorithms in Data Structures and Algorithms (DSA) involve manipulating individual bits of binary representations of numbers to perform operations efficiently. These algorithms utilize bitwise operators like AND, OR, XOR, NOT, Left Shift, and Right Shift.BasicsIntroduction to Bitwise Algorit
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Advanced
Segment TreeSegment Tree is a data structure that allows efficient querying and updating of intervals or segments of an array. It is particularly useful for problems involving range queries, such as finding the sum, minimum, maximum, or any other operation over a specific range of elements in an array. The tree
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Pattern SearchingPattern searching algorithms are essential tools in computer science and data processing. These algorithms are designed to efficiently find a particular pattern within a larger set of data. Patten SearchingImportant Pattern Searching Algorithms:Naive String Matching : A Simple Algorithm that works i
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GeometryGeometry is a branch of mathematics that studies the properties, measurements, and relationships of points, lines, angles, surfaces, and solids. From basic lines and angles to complex structures, it helps us understand the world around us.Geometry for Students and BeginnersThis section covers key br
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