Switch to Dark Mode

Java Array Programs

Here are 10 essential multiple-choice questions on Java Array Programs, covering key concepts.

Last Updated : Mar 26, 2025

Discuss

Comments

Question 1

What will be the output of the following program?

Java

int[] arr = {5, 10, 15, 20, 25};
int sum = 0;
for (int num : arr) {
    sum += num;
}
System.out.println(sum);

A
50
B
60
C
55
D
65

Discuss it

Question 2

How do you find the largest element in an array in Java?

A
Using Collections.max(arr)
B
Iterating and comparing each element
C
Using Math.max(arr)
D
Sorting and taking the first element

Discuss it

Question 3

What will be the output of the following code?

Java

int[] arr = {3, 1, 4, 1, 5, 9};
Arrays.sort(arr);
System.out.println(arr[0]);

Discuss it

Question 4

What is the best way to reverse an array in Java?

A
Using Collections.reverse()
B
Using a loop with swapping
C
Using Arrays.reverse()
D
Using Math.reverse()

Discuss it

Question 5

What will be the output of the following program?

Java

int[] arr = {1, 2, 3, 4, 5};
System.out.println(arr.length);

A
4
B
5
C
6
D
Compilation Error

Discuss it

Question 6

How do you check if two arrays are equal in Java?

A
arr1 == arr2
B
Arrays.equals(arr1, arr2)
C
arr1.equals(arr2)
D
arr1.compare(arr2)

Discuss it

Question 7

What will be the output of the following program?

Java

int[] arr1 = {1, 2, 3};
int[] arr2 = arr1;
arr2[0] = 10;
System.out.println(arr1[0]);

A
1
B
10
C
Compilation Error
D
Runtime Error

Discuss it

Question 8

What is the correct way to copy an array in Java?

A
arr2 = arr1;
B
arr2 = Arrays.copyOf(arr1, arr1.length);
C
arr2.clone(arr1);
D
Arrays.copy(arr1, arr2);

Discuss it

Question 9

How do you find duplicate elements in an array?

A
Using HashSet
B
Using arr.contains()
C
Using arr.duplicates()
D
Java does not support duplicate detection

Discuss it

Question 10

What is the time complexity of linear search in an array?

A
O(1)
B
O(log n)
C
O(n)
D
O(n^2)

Discuss it

Tags:

Java Quiz

There are 10 questions to complete.

Take a part in the ongoing discussion