Python3 Program to Find Maximum value possible by rotating digits of a given number
Last Updated :
06 Sep, 2024
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Given a positive integer N, the task is to find the maximum value among all the rotations of the digits of the integer N.
Examples:
Input: N = 657
Output: 765
Explanation: All rotations of 657 are {657, 576, 765}. The maximum value among all these rotations is 765.Input: N = 7092
Output: 9270
Explanation:
All rotations of 7092 are {7092, 2709, 9270, 0927}. The maximum value among all these rotations is 9270.
Approach: The idea is to find all rotations of the number N and print the maximum among all the numbers generated. Follow the steps below to solve the problem:
- Count the number of digits present in the number N, i.e. upper bound of log10N.
- Initialize a variable, say ans with the value of N, to store the resultant maximum number generated.
- Iterate over the range [1, log10(N) - 1] and perform the following steps:
- Update the value of N with its next rotation.
- Now, if the next rotation generated exceeds ans, then update ans with the rotated value of N
- After completing the above steps, print the value of ans as the required answer.
Below is the implementation of the above approach:
# Python program for the above approach
# Function to find the maximum value
# possible by rotations of digits of N
def findLargestRotation(num):
# Store the required result
ans = num
# Store the number of digits
length = len(str(num))
x = 10**(length - 1)
# Iterate over the range[1, len-1]
for i in range(1, length):
# Store the unit's digit
lastDigit = num % 10
# Store the remaining number
num = num // 10
# Find the next rotation
num += (lastDigit * x)
# If the current rotation is
# greater than the overall
# answer, then update answer
if (num > ans):
ans = num
# Print the result
print(ans)
# Driver Code
N = 657
findLargestRotation(N)
# This code is contributed by rohitsingh07052.
# Python program for the above approach
# Function to find the maximum value
# possible by rotations of digits of N
def findLargestRotation(num):
# Store the required result
ans = num
# Store the number of digits
length = len(str(num))
x = 10**(length - 1)
# Iterate over the range[1, len-1]
for i in range(1, length):
# Store the unit's digit
lastDigit = num % 10
# Store the remaining number
num = num // 10
# Find the next rotation
num += (lastDigit * x)
# If the current rotation is
# greater than the overall
# answer, then update answer
if (num > ans):
ans = num
# Print the result
print(ans)
# Driver Code
N = 657
findLargestRotation(N)
# This code is contributed by rohitsingh07052.
Output
765
Time Complexity: O(log10N)
Auxiliary Space: O(1)
Please refer complete article on
Maximum value possible by rotating digits of a given numberfor more details!