sympy.integrals.transforms.mellin_transform() in python

sympy.integrals.transforms.laplace_transform() in python

Last Updated : 04 Feb, 2023

With the help of laplace_transform() method, we can compute the laplace transformation F(s) of f(t).

Syntax : laplace_transform(f, t, s)
Return : Return the laplace transformation and convergence condition.

Example #1 :
In this example, we can see that by using laplace_transform() method, we are able to compute the laplace transformation and return the transformation and convergence condition.

Python3

# import laplace_transform
from sympy.integrals import laplace_transform
from sympy.abc import t, s, a

# Using laplace_transform() method
gfg = laplace_transform(t**a, t, s)

print(gfg)

Output :

(s**(-a)*gamma(a + 1)/s, 0, a > -1)

Example #2 :

Python3

# import laplace_transform
from sympy.integrals import laplace_transform
from sympy.abc import t, s, a

# Using laplace_transform() method
gfg = laplace_transform(t**a, t, 5)

print(gfg)

Output :

(5**(-a)*gamma(a + 1)/5, 0, a > -1)

Example #3:

Python3

# import laplace_transform
from sympy.integrals import laplace_transform
from sympy import sin 
from sympy.abc import t, s, a

# Using laplace_transform() method
gfg = laplace_transform(sin(a*t), t, s)

print(gfg)

Output :

(a/(a**2 + s**2), 0, Eq(2*Abs(arg(a)), 0))

sympy.integrals.transforms.mellin_transform() in python

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