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numpy.less() in Python

Last Updated : 08 Mar, 2024
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The numpy.less() : checks whether x1 is lesser than x2 or not. Syntax : 

numpy.less(x1, x2[, out])

Parameters : 

x1, x2 : [array_like]Input arrays. If x1.shape != x2.shape, they must be 
             broadcastable to a common shape 
out    : [ndarray, boolean]Array of bools, or a single bool if x1 and x2 are scalars.

Return : 

Boolean array indicating results, whether x1 is lesser than x2 or not.

Code 1 : 

Python 
# Python Program illustrating
# numpy.less() method
 
import numpy as geek 

a  = geek.less([8., 2.], [5., 3.])
print("Not equal : \n", a, "\n")

b = geek.less([2, 2], [[1, 3],[1, 4]])
print("Not equal : \n", b, "\n")

a = geek.array([4,2])
b = geek.array([6,2])

print("Is a lesser than b : ", a < b)

Output : 

Not equal : 
 [False  True] 

Not equal : 
 [[False  True]
 [False  True]] 

Is a lesser than b :  [ True False]]

Code 2 : 

Python 
# Python Program illustrating
# numpy.less() method
  
import numpy as geek 
 
# Here we will compare Complex values with int 
a = geek.array([1j,2])
b = geek.array([1,2])
 
# indicating 1j is lesser than 1
print("Comparing complex with int : ", a < b)

# indicating 1j is lesser than 1
d  = geek.less(a, b)
print("\n Comparing complex with int  .less() : ", d)

Output : 

Comparing complex with int :  [ True False]

 Comparing complex with int  .less() :  [ True False]

Code 3 : 

Python 
# Python Program illustrating
# numpy.less() method
  
import numpy as geek 

# Here we will compare Float with int values
a = geek.array([1.1, 1])
b = geek.array([1, 2])
 
# indicating 1.1 is greater than 1
print("Comparing float with int : ", a < b)

# indicating 1.1 is greater than 1
d  = geek.less(a, b)
print("\n Comparing float with int using  .less() : ", d)

Output : 

Comparing float with int :  [False  True]

 Comparing float with int using  .less() :  [False  True]

M

Mohit Gupta
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