numpy.arccos() in Python Last Updated : 08 Mar, 2024 Comments Improve Suggest changes Like Article Like Report numpy.arccos(x[, out]) = ufunc 'arccos') : This mathematical function helps user to calculate inverse cos for all x(being the array elements). Parameters : array : [array_like]elements are in radians. out : [array_like]array of same shape as x. Note : 2pi Radians = 360 degrees The convention is to return the angle z whose real part lies in [0, pi]. Return : An array with inverse cosine of x for all x i.e. array elements. The values are in the closed interval [-pi/2, pi/2]. Code #1 : Working Python3 # Python program explaining # arccos() function import numpy as np in_array = [0, 1, 0.3, -1] print ("Input array : \n", in_array) arccos_Values = np.arccos(in_array) print ("\nInverse Cosine values : \n", arccos_Values) Output : Input array : [0, 1, 0.3, -1] Inverse Cosine values : [ 1.57079633 0. 1.26610367 3.14159265] Code #2 : Graphical representation Python3 # Python program showing # Graphical representation # of arccos() function import numpy as np import matplotlib.pyplot as plt in_array = np.linspace(-np.pi, np.pi, 12) out_array1 = np.cos(in_array) out_array2 = np.arccos(in_array) print("in_array : ", in_array) print("\nout_array with cos : ", out_array1) print("\nout_arraywith arccos : ", out_array1) # red for numpy.arccos() plt.plot(in_array, out_array1, color = 'blue', marker = "*") plt.plot(in_array, out_array2, color = 'red', marker = "o") plt.title("blue : numpy.cos() \nred : numpy.arccos()") plt.xlabel("X") plt.ylabel("Y") plt.show() Output : in_array : [-3.14159265 -2.57039399 -1.99919533 -1.42799666 -0.856798 -0.28559933 0.28559933 0.856798 1.42799666 1.99919533 2.57039399 3.14159265] out_array with cos : [-1. -0.84125353 -0.41541501 0.14231484 0.65486073 0.95949297 0.95949297 0.65486073 0.14231484 -0.41541501 -0.84125353 -1. ] out_arraywith arccos : [-1. -0.84125353 -0.41541501 0.14231484 0.65486073 0.95949297 0.95949297 0.65486073 0.14231484 -0.41541501 -0.84125353 -1. ] RuntimeWarning: invalid value encountered in arccos out_array1 = np.sin(in_array) Comment More info M mohit gupta_omg :) Follow Improve Article Tags : Python Python-numpy Python numpy-Mathematical Function Explore Python FundamentalsPython Introduction 3 min read Input and Output in Python 4 min read Python Variables 5 min read Python Operators 5 min read Python Keywords 2 min read Python Data Types 8 min read Conditional Statements in Python 3 min read Loops in Python - For, While and Nested Loops 7 min read Python Functions 5 min read Recursion in Python 6 min read Python Lambda Functions 5 min read Python Data StructuresPython String 5 min read Python Lists 5 min read Python Tuples 4 min read Dictionaries in Python 3 min read Python Sets 6 min read Python Arrays 7 min read List Comprehension in Python 4 min read Advanced PythonPython OOP Concepts 11 min read Python Exception Handling 5 min read File Handling in Python 4 min read Python Database Tutorial 4 min read Python MongoDB Tutorial 2 min read Python MySQL 9 min read Python Packages 12 min read Python Modules 7 min read Python DSA Libraries 15 min read List of Python GUI Library and Packages 3 min read Data Science with PythonNumPy Tutorial - Python Library 3 min read Pandas Tutorial 6 min read Matplotlib Tutorial 5 min read Python Seaborn Tutorial 15+ min read StatsModel Library- Tutorial 4 min read Learning Model Building in Scikit-learn 8 min read TensorFlow Tutorial 2 min read PyTorch Tutorial 7 min read Web Development with PythonFlask Tutorial 8 min read Django Tutorial | Learn Django Framework 7 min read Django ORM - Inserting, Updating & Deleting Data 4 min read Templating With Jinja2 in Flask 6 min read Django Templates 7 min read Python | Build a REST API using Flask 3 min read How to Create a basic API using Django Rest Framework ? 4 min read Python PracticePython Quiz 3 min read Python Coding Practice 1 min read Python Interview Questions and Answers 15+ min read Like