Python | SymPy Permutation.cycles() method

Last Updated : 26 Aug, 2019

Permutation.cycles() : cycles() is a sympy Python library function that returns the number of cycles present in the permutation. This also includes the singleton.

Syntax : sympy.combinatorics.permutations.Permutation.cycles() Return : number of cycles present in the permutation

Code #1 : cycles() Example

Python3 1=1

# Python code explaining
# SymPy.Permutation.cycles()

# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation

# Using from sympy.combinatorics.permutations.Permutation.cycles() method 

# creating Permutation
a = Permutation([2, 0, 3, 1, 5, 4])

b = Permutation([3, 1, 2, 5, 4, 0])


print ("Permutation a - cycles form : ", a.cycles)
print ("Permutation b - cycles form : ", b.cycles)

Output :

Permutation a - cycles form : 2 Permutation b - cycles form : 4

Code #2 : cycles() Example - 2D Permutation

Python3 1=1

# Python code explaining
# SymPy.Permutation.cycles()

# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation

# Using from 
# sympy.combinatorics.permutations.Permutation.cycles() method 

# creating Permutation
a = Permutation([[2, 4, 0], 
                 [3, 1, 2],
                 [1, 5, 6]])

# SELF COMMUTATING    
print ("Permutation a - cycles form : ", a.cycles)

Output :

Permutation a - cycles form : 1

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Python | SymPy Permutation.cycles() method

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