Python | SymPy combinatorics.prev_lex() method Last Updated : 26 Aug, 2019 Comments Improve Suggest changes Like Article Like Report With the help of sympy.combinatorics.partitions.IntegerPartition().prev_lex() method, we can get the previous partition of integer n in lexical order by using sympy.combinatorics.partitions.IntegerPartition().prev_lex() method. Syntax : sympy.combinatorics.partitions.IntegerPartition().prev_lex() Return : Return the lexical value of previous partition of integer n. Example #1 : In this example we can see that by using sympy.combinatorics.partitions.IntegerPartition().prev_lex() method, we are able to get the lexical value of previous partition of integer n. Python3 1=1 # import sympy and IntegerPartition from sympy.combinatorics.partitions import IntegerPartition from sympy import * # Using sympy.combinatorics.partitions.IntegerPartition().prev_lex() method gfg = IntegerPartition([1, 2, 3]) print(gfg.prev_lex()) Output : [3, 1, 1, 1] Example #2 : Python3 1=1 # import sympy and IntegerPartition from sympy.combinatorics.partitions import IntegerPartition from sympy import * # Using sympy.combinatorics.partitions.IntegerPartition().prev_lex() method gfg = IntegerPartition([1, 2, 3, 4, 3, 2, 1]) print(gfg.prev_lex()) Output : [4, 3, 3, 2, 1, 1, 1, 1] Comment More infoAdvertise with us Next Article Python | SymPy combinatorics.prev_lex() method J jitender_1998 Follow Improve Article Tags : Python SymPy Practice Tags : python Similar Reads Python | SymPy combinatorics.next_lex() method With the help of sympy.combinatorics.partitions.IntegerPartition().next_lex() method, we can get the next partition of integer n in lexical order by using sympy.combinatorics.partitions.IntegerPartition().next_lex() method. Syntax : sympy.combinatorics.partitions.IntegerPartition().next_lex() Return 1 min read Python | sympy.compare() method With the help of sympy.compare() method, we can compare the variables and it will return 3 values i.e -1 for smaller, 0 for equal and 1 for greater by using sympy.compare() method. Syntax : sympy.compare() Return : Return the value of comparison i.e -1, 0, 1. Example #1 : In this example we can see 1 min read Python | sympy.binomial() method With the help of sympy.binomial() method, we can find the number of ways to choose k items from a set of n distinct items. It is also often written as nCk, and is pronounced “n choose kâ€. \begin{equation} \binom{N}{k} \end{equation} Syntax: binomial(N, K) Parameters: N - It denotes the number of ite 1 min read SymPy | Partition.prev_lex() in Python Partition.prev_lex() : prev_lex() is a sympy Python library function that returns the previous integer partition, n in lexicographical order. This ordering wraps around [n] if the partition is [1, …, 1]. Syntax : sympy.combinatorics.partitions.Partition.prev_lex()Return : previous integer partition 1 min read Python | sympy.combsimp() method With the help of sympy.combsimp() method, we can simplify combinatorial expressions. Syntax: combsimp(expression) Parameter: expression - It is combinatorial expression which needs to be simplified. Returns: Returns a simplified mathematical expression corresponding to the input. Example #1: Python3 1 min read Like