Open In App

Python | SymPy combinatorics.next_lex() method

Last Updated : 26 Aug, 2019
Comments
Improve
Suggest changes
Like Article
Like
Report
With the help of sympy.combinatorics.partitions.IntegerPartition().next_lex() method, we can get the next partition of integer n in lexical order by using sympy.combinatorics.partitions.IntegerPartition().next_lex() method.
Syntax : sympy.combinatorics.partitions.IntegerPartition().next_lex() Return : Return the lexical value of next partition of integer n.
Example #1 : In this example we can see that by using sympy.combinatorics.partitions.IntegerPartition().next_lex() method, we are able to get the lexical value of next partition of integer n. Python3 1=1
# import sympy and IntegerPartition
from sympy.combinatorics.partitions import IntegerPartition
from sympy import *
  
# Using sympy.combinatorics.partitions.IntegerPartition().next_lex() method
gfg = IntegerPartition([1, 2, 3])
  
print(gfg.next_lex())
Output :
[3, 3]
Example #2 : Python3 1=1
# import sympy and IntegerPartition
from sympy.combinatorics.partitions import IntegerPartition
from sympy import *
  
# Using sympy.combinatorics.partitions.IntegerPartition().next_lex() method
gfg = IntegerPartition([1, 2, 3, 4, 3, 2, 1])
  
print(gfg.next_lex())
Output :
[4, 3, 3, 2, 2, 2]

Next Article
Article Tags :
Practice Tags :

Similar Reads