Print odd numbers in a List - Python

We are given a list and our task is to print all the odd numbers from it. This can be done using different methods like a simple loop, list comprehension, or the filter() function. For example, if the input is [1, 2, 3, 4, 5], the output will be [1, 3, 5].

Using Loop

The most basic way to print odd numbers in a list is to use a for loop with if conditional check to identify odd numbers.

a = [10, 15, 23, 42, 37, 51, 62, 5]

for i in a:
    if i % 2 != 0:
        print(i)

15
23
37
51
5

Explanation:

• Loops through list a.
• For each element i, checks if i % 2 != 0 (i.e., if the number is odd).
• If the condition is true then print the odd number.

Using List Comprehension

List comprehension is similar to the for loop method shown above but offers a more concise way to filter odd numbers from a list.

a = [10, 15, 23, 42, 37, 51, 62, 5]

res = [i for i in a if i % 2 != 0]

print(res)

[15, 23, 37, 51, 5]

Explanation: This list comprehension filters all elements in a where i % 2 != 0 (i.e., the number is odd).

Using filter() Function

The filter() function can also be used to filter out odd numbers. The filter() function applies a function to each item in the iterable and returns a filter object containing only those items where the function returns True.

a = [10, 15, 23, 42, 37, 51, 62, 5]

res = filter(lambda x: x % 2 != 0, a)

print(list(res))

[15, 23, 37, 51, 5]

Explanation:

• filter() function takes two arguments: a lambda function (lambda x: x % 2 != 0) that checks if the number is odd and the iterable 'a'.
• The result is a filter object which we convert to a list and print.

Related Articles:

• Python For Loops
• List Comprehension in Python
• filter() in python