Python Program For Deleting A Linked List Node At A Given Position Last Updated : 15 Jun, 2022 Summarize Comments Improve Suggest changes Share Like Article Like Report Given a singly linked list and a position, delete a linked list node at the given position. Example: Input: position = 1, Linked List = 8->2->3->1->7 Output: Linked List = 8->3->1->7 Input: position = 0, Linked List = 8->2->3->1->7 Output: Linked List = 2->3->1->7Recommended: Please solve it on "PRACTICE" first, before moving on to the solution. If the node to be deleted is the root, simply delete it. To delete a middle node, we must have a pointer to the node previous to the node to be deleted. So if positions are not zero, we run a loop position-1 times and get a pointer to the previous node. Below is the implementation of the above idea. Python # Python program to delete a node in a linked list # at a given position # Node class class Node: # Constructor to initialize the node object def __init__(self, data): self.data = data self.next = None class LinkedList: # Constructor to initialize head def __init__(self): self.head = None # Function to insert a new node at the beginning def push(self, new_data): new_node = Node(new_data) new_node.next = self.head self.head = new_node # Given a reference to the head of a list # and a position, delete the node at a given position def deleteNode(self, position): # If linked list is empty if self.head == None: return # Store head node temp = self.head # If head needs to be removed if position == 0: self.head = temp.next temp = None return # Find previous node of the node to be deleted for i in range(position -1 ): temp = temp.next if temp is None: break # If position is more than number of nodes if temp is None: return if temp.next is None: return # Node temp.next is the node to be deleted # store pointer to the next of node to be deleted next = temp.next.next # Unlink the node from linked list temp.next = None temp.next = next # Utility function to print the linked LinkedList def printList(self): temp = self.head while(temp): print " %d " %(temp.data), temp = temp.next # Driver program to test above function llist = LinkedList() llist.push(7) llist.push(1) llist.push(3) llist.push(2) llist.push(8) print "Created Linked List: " llist.printList() llist.deleteNode(4) print " Linked List after Deletion at position 4: " llist.printList() # This code is contributed by Nikhil Kumar Singh(nickzuck_007) Output: Created Linked List: 8 2 3 1 7 Linked List after Deletion at position 4: 8 2 3 1 Time Complexity: O(n), where n represents the length of the given linked list.Auxiliary Space: O(1), no extra space is required, so it is a constant. Please refer complete article on Delete a Linked List node at a given position for more details! Comment More infoAdvertise with us Next Article Delete alternate nodes of a Linked List K kartik Follow Improve Article Tags : Python Linked Lists Samsung Python-DSA Practice Tags : Samsungpython Similar Reads Delete a Linked List node at a given position Given a singly linked list and a position (1-based indexing), the task is to delete a linked list node at the given position.Note: Position will be valid (i.e, 1 <= position <= linked list length)Example: Input: position = 2, Linked List = 8->2->3->1->7Output: Linked List = 8->3 8 min read Javascript Program To Delete Alternate Nodes Of A Linked List Given a Singly Linked List, starting from the second node delete all alternate nodes of it. For example, if the given linked list is 1->2->3->4->5 then your function should convert it to 1->3->5, and if the given linked list is 1->2->3->4 then convert it to 1->3.Method 4 min read Javascript Program To Delete N Nodes After M Nodes Of A Linked List Given a linked list and two integers M and N. Traverse the linked list such that you retain M nodes then delete next N nodes, continue the same till end of the linked list.Difficulty Level: Rookie Examples:Input:M = 2, N = 2Linked List: 1->2->3->4->5->6->7->8Output:Linked List: 3 min read Delete alternate nodes of a Linked List Given a Singly Linked List, starting from the second node delete all alternate nodes of it. For example, if the given linked list is 1->2->3->4->5 then your function should convert it to 1->3->5, and if the given linked list is 1->2->3->4 then convert it to 1->3. Recomm 14 min read Python - Print list after removing element at given index In this article, we will explore different ways to remove an element from a list at a given index and print the updated list, offering multiple approaches for achieving this.Using pop()pop() method removes the element at a specified index and returns it.Pythonli = [10, 20, 30, 40, 50] index = 2 li.p 2 min read Given only a pointer/reference to a node to be deleted in a singly linked list, how do you delete it? Given a pointer to a node to be deleted, delete the node. Note that we donât have a pointer to the head node.Examples:Input: list = 10 -> 20 -> 4 -> 30, delNode = 20Output: 10 -> 4 -> 30Explanation: Node with value 20 is deleted.Input: list = 1 -> 2, delNode = 1Output: 2Explanation 7 min read Like