Python | Numpy np.legvander() method

Python | Numpy np.legone() method

Last Updated : 31 Dec, 2019

np.legone() method can be used instead of np.ones for creating a array whose elements are 1.

Syntax : np.legone() Return : Return array([1])

Example #1 :

Python3 1=1

  
# Python program explaining
# numpy.legone() method 

# import numpy and legone
import numpy as np
from numpy.polynomial.legendre import legone

# using np.legone() method
ans = legone

print(ans)

Output :

[1]

Example #2 :

Python3 1=1

# Python program explaining
# numpy.legone() method 

# import numpy and legone
import numpy as np
from numpy.polynomial.legendre import legone

# using np.legone() method
ans = legone + [[1, 3, 5], [2, 4, 6]]

print(ans)

Output :

[[2 4 6] [3 5 7]]

Python | Numpy np.legvander() method

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