Python | Numpy getmask() method

python | Numpy masked_equal() method

Last Updated : 19 Sep, 2019

With the help of numpy.ma.masked_equal() method, we can get the mask a value that in an array by using numpy.ma.masked_equal() method.

Syntax : numpy.ma.masked_equal(array, value) Return : Return the array after removing mask value.

Example #1 : In this example we can see that by using numpy.ma.masked_equal() method, we are able to get the new array after removing mask value which is passed along with an array.

Python3 1=1

# import numpy
import numpy.ma as ma

# using numpy.ma.masked_equal() method
gfg = ma.masked_equal([1, 2, 3, 4], 3)

print(gfg)

Output :

[1 2 -- 4]

Example #2 :

Python3 1=1

# import numpy
import numpy.ma as ma

# using numpy.ma.masked_equal() method
gfg = ma.masked_equal([[1, 2, 3, 4],
                       [6, 7, 8, 9]], 6)

print(gfg)

Output :

[[1 2 3 4] [-- 7 8 9]]

Python | Numpy getmask() method

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