Python - Flag None Element Rows in Matrix

# Python3 code to demonstrate working of 
# Flag None Element Rows in Matrix
# Using list comprehension

# initializing list
test_list = [[2, 4, None, 3], [3, 4, 1, None], [2, 4, 7, 4], [2, 8]]

# printing original list
print("The original list is : " + str(test_list))

# in operator to check None value 
# True if any None is found 
res = [True if None in sub else False for sub in test_list]

# printing result 
print("None Flagged List : " + str(res))

# Python3 code to demonstrate working of 
# Flag None Element Rows in Matrix
# Using all() + list comprehension

# initializing list
test_list = [[2, 4, None, 3], [3, 4, 1, None], [2, 4, 7, 4], [2, 8]]

# printing original list
print("The original list is : " + str(test_list))

# all() checks for all non none values  
res = [False if all(sub) else True for sub in test_list]

# printing result 
print("None Flagged List : " + str(res))

# Python3 code to demonstrate working of
# Flag None Element Rows in Matrix

# initializing list
test_list = [[2, 4, None, 3], [3, 4, 1, None], [2, 4, 7, 4], [2, 8]]

# printing original list
print("The original list is : " + str(test_list))
res = []
for i in test_list:
    if i.count(None) >= 1:
        res.append(True)
    else:
        res.append(False)

# printing result
print("None Flagged List : " + str(res))

test_list = [[2, 4, None, 3], [3, 4, 1, None], [2, 4, 7, 4], [2, 8]]

print("The original list is : " + str(test_list))

res = []
for sub in test_list:
    if None in sub:
        res.append(True)
    else:
        res.append(False)

print("None Flagged List : " + str(res))
#This code is contributed by Vinay pinjala.

test_list = [[2, 4, None, 3], [3, 4, 1, None], [2, 4, 7, 4], [2, 8]]
print("The original list is : " + str(test_list))

# Method 5: Using any() function with a generator expression
res = [any(val is None for val in sub) for sub in test_list]

print("None Flagged List : " + str(res))