Python - Filter dictionaries with ordered values

# Python3 code to demonstrate working of
# Filter dictionaries with ordered values
# Using sorted() + values() + list comprehension

# initializing list
test_list = [{'gfg': 2, 'is': 8, 'good': 10},
             {'gfg': 1, 'for': 10, 'geeks': 9},
             {'love': 3, 'gfg': 4}]

# printing original list
print("The original list is : " + str(test_list))

# sorted to check with ordered values
# values() extracting dictionary values
res = [sub for sub in test_list if sorted(
    list(sub.values())) == list(sub.values())]

# printing result
print("The filtered Dictionaries : " + str(res))

# Python3 code to demonstrate working of
# Filter dictionaries with ordered values
# Using filter() + lambda + sorted()

# initializing list
test_list = [{'gfg': 2, 'is': 8, 'good': 10},
             {'gfg': 1, 'for': 10, 'geeks': 9},
             {'love': 3, 'gfg': 4}]

# printing original list
print("The original list is : " + str(test_list))

# sorted to check with ordered values
# values() extracting dictionary values
# filter() and lambda function used to filter
res = list(filter(lambda sub: sorted(list(sub.values()))
                  == list(sub.values()), test_list))

# printing result
print("The filtered Dictionaries : " + str(res))

# Python3 code to demonstrate working of
# Filter dictionaries with ordered values

# initializing list
test_list = [{'gfg': 2, 'is': 8, 'good': 10},
             {'gfg': 1, 'for': 10, 'geeks': 9},
             {'love': 3, 'gfg': 4}]

# printing original list
print("The original list is : " + str(test_list))

res = []

for i in test_list:
  
    y = []
    x = list(i.values())
    y.extend(x)
    y.sort()
    if(x == y):
        res.append(i)


# printing result
print("The filtered Dictionaries : " + str(res))

# Python3 code to demonstrate working of
# Filter dictionaries with ordered values
# Using a loop and a flag variable

# Initializing list
test_list = [{'gfg': 2, 'is': 8, 'good': 10},
             {'gfg': 1, 'for': 10, 'geeks': 9},
             {'love': 3, 'gfg': 4}]

# Printing original list
print("The original list is : " + str(test_list))

# Looping through each dictionary and
# check for ordered values
res = []

for d in test_list:
    values = list(d.values())
    ordered = True
    for i in range(len(values) - 1):
        if values[i] > values[i+1]:
            ordered = False
            break
    if ordered:
        res.append(d)

# Printing the result
print("The filtered Dictionaries : " + str(res))