Overriding methods from different packages in Java Last Updated : 22 Jun, 2020 Comments Improve Suggest changes Like Article Like Report Prerequisite : Overriding in Java, Packages in Java Packages provide more layer of encapsulation for classes. Thus, visibility of a method in different packages is different from that in the same package. How JVM find which method to call? When we run a java program, JVM checks the runtime class of the object. JVM checks whether the object's runtime class has overridden the method of the declared class. If so, that's the method called. Otherwise, declared class's method is called. Thus, the key point is visible check the visibility of method in different packages. Following are the cases where we will see method overriding in different packages 1. Private method overriding : In this, access modifier of method we want to override is private. Java // Filename: Hello.java package a; public class Hello { private void printMessage() { System.out.println("Hello"); } public void fun() { printMessage(); } } // Filename: World.java package b; import a.Hello; public class World extends Hello { private void printMessage() { System.out.println("World"); } public static void main(String[] args) { Hello gfg = new World(); gfg.fun(); } } Output: Hello As private method of parent class is not visible in child class. Thus no overriding takes place here. If you don't know how to run this program from terminal then, create Hello.java file and World.java file as specified above and run these commands. 2. Public method overriding : In this, access modifier of method we want to override is public. Java // Hello.java package a; public class Hello { public void printMessage() { System.out.println("Hello"); } } // World.java package b; import a.Hello; public class World extends Hello { public void printMessage() { System.out.println("World"); } public static void main(String[] args) { Hello gfg = new World(); gfg.printMessage(); } } Output: World Public method is accessible everywhere, hence when printMessage() is called, jvm can find the overridden method and thus call it. Thus overriding takes place here. 3. Default method overriding Java // Hello.java package a; public class Hello { void printMessage() { System.out.println("Hello"); } } // World.java package b; import a.Hello; public class World extends Hello { void printMessage() { System.out.println("World"); } public static void main(String[] args) { Hello gfg = new World(); gfg.printMessage(); } } error: printMessage() is not public in Hello; cannot be accessed from outside package Visibility of a default method is within its package only. Hence it can't be access outside the package. Thus, no overriding in this case. Predict the output of the following program Java /* Hello.java */ package a; public class Hello { public void doIt() { printMessage(); } void printMessage() { System.out.println("Hello"); } } /* World.java */ package b; import a.Hello; public class World { private static class GFG extends Hello { void printMessage() { System.out.println("World"); } } public static void main(String[] args) { GFG gfg = new GFG(); gfg.doIt(); } } Output: Hello Explanation Visibility of printMessage() is default in package a. Thus, no overriding takes place here. Comment More infoAdvertise with us Next Article Introduction to Java S Shubham Juneja Improve Article Tags : Java java-inheritance Java-Packages java-overriding Practice Tags : Java Similar Reads Java Tutorial Java is a high-level, object-oriented programming language used to build web apps, mobile applications, and enterprise software systems. 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