numpy.nper() in Python

numpy.nper() in Python

Last Updated : 28 Nov, 2018

numpy.pmt(rate, pmt, pv, fv, when = ‘end’) : This financial function helps user to compute number of periodic payments.

Parameters : rate : [scalar or (M, )array] Rate of interest as decimal (not per cent) per period pmt : [scalar or (M, )array] Payment value fv : [scalar or (M, )array] Future value pv : [scalar or (M, )array] present value when : at the beginning (when = {‘begin’, 1}) or the end (when = {‘end’, 0}) of each period. Default is {‘end’, 0}. Return : Number of periodic payments.

Equation being solved :

fv + pv*(1+rate)**nper + pmt*(1 + rate*when)/rate*((1 + rate)**nper - 1) == 0 or when rate == 0 fv + pv + pmt * nper == 0

Code:

Python3 1==

# Python program explaining 
# pmt() function 

import numpy as np 

''' 
Question : 

how much time would it take to pay-off a loan of 
$10, 000 at 10 % annual rate of interest, if we had 
$100 to pay each month ? 
'''

# rate    pmt    pv 
Solution = np.nper(0.1 / 12, -100, 10000) 

# Here fv = 0 ; Also Default value of fv = 0 
print("Solution - No. of periods : % f months" %(Solution))

Output:

Solution - No. of periods : 215.905777 months

numpy.nper() in Python

mohit gupta_omg :)

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