numpy.in1d() function in Python

numpy.in1d() function test whether each element of a 1-D array is also present in a second array and return a boolean array the same length as arr1 that is True where an element of arr1 is in arr2 and False otherwise.

Syntax : numpy.in1d(arr1, arr2, assume_unique = False, invert = False) Parameters : arr1 : [array_like] Input array. arr2 : [array_like] The values against which to test each value of arr1. assume_unique : [bool, optional] If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False. invert : [bool, optional] If True, the values in the returned array are inverted. Default is False. Return : [ndarray, bool] The values arr1[in1d] are in arr2.

Code #1 : Python3

# Python program explaining
# numpy.in1d() function
  
# importing numpy as geek 
import numpy as geek 
 
arr1 = geek.array([0, 1, 2, 3, 0, 4, 5])
arr2 = [0, 2, 5]
 
gfg = geek.in1d(arr1, arr2)
 
print (gfg)

Output :

[ True False True False True False True]

  Code #2 : Python3

# Python program explaining
# numpy.in1d() function
  
# importing numpy as geek 
import numpy as geek 
 
arr1 = geek.array([0, 1, 2, 3, 0, 4, 5])
arr2 = [0, 2, 5]
 
gfg = geek.in1d(arr1, arr2, invert = True)
 
print (gfg)

Output :

[False True False True False True False]