Node.js URLSearchParams.getAll()

Last Updated : 14 Oct, 2021

In URLSearchParams interface, the getAll() method returns all the values of the input search parameter in the form of an array. Syntax:

URLSearchParams.getAll(name)

Returns: An array of string according to the name-value pairs, else an empty array will be returned. Parameters: name - Input the name of the parameter. Example1:

javascript

let url = new URL('https://example.com?par=5&bar=2'); 
let params = new URLSearchParams(url.search.slice(1)); 

//Add a second par parameter. 
params.append('par', 4);

console.log(params.getAll('par'))'

Output:

['5', '4']

Example2: When input parameter is not present

javascript

let url = new URL('https://example.com?par=5&bar=2&bar=7&par=4&bar=9'); 
let params = new URLSearchParams(url.search.slice(1)); 

console.log(params.getAll('bar'))'

Output:

['2','7','9']

Supported Browsers:

Google Chrome
IE
Edge
Opera
Apple Safari

Node.js URLSearchParams.sort()

DeepakDev

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Node.js URLSearchParams.getAll()

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