Node.js URLSearchParams.delete()

Last Updated : 14 Oct, 2021

In URLSearchParams interface, the delete() method deletes the parameter specified by user and all its associated values.

Syntax:

URLSearchParams.delete(name)

Parameters:
name – The name of the parameter to be deleted.

Example 1:

let url = new URL('https://example.com?par=1&bar=2&par=3'); 
let params = new URLSearchParams(url.search.slice(1)); 
  
// Delete the par parameter. 
params.delete('par'); 
console.log(url) 

Output:

https://example.com?bar=2

Example 2:

let url = new URL('https://example.com?foo=1&par=3'); 
let params = new URLSearchParams(url.search.slice(1)); 
  
// Delete the foo parameter. 
params.delete('foo'); 
console.log(url) 

Output:

https://example.com?par=3

Supported Browsers:

Google Chrome
IE
Edge
Opera
Apple Safari

Node.js URLSearchParams.entries()

DeepakDev

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Article Tags :

JavaScript
Node.js
Web Technologies
Node-URL

Node.js URLSearchParams.delete()

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