Minimum flips required to keep all 1s together in a Binary string Last Updated : 12 Jul, 2025 Comments Improve Suggest changes Like Article Like Report Given binary string str, the task is to find the minimum number of flips required to keep all 1s together in the given binary string, i.e. there must not be any 0 between 1s in the string. Examples: Input: str = "0011111100" Output: 0 Explanation: We dont need to flip any bits because all the ones are grouped together and there is no zero between any two ones. Input: str = "11100111000101" Output: 4 Explanation: We can flip the 4th and 5th bit to make them 1 and flip 12th and 14th bit to make them 0. So the resulting string is "11111111000000" with 4 possible flips. Approach: To solve the problem mentioned above we will implement the dynamic programming approach where we will have the following states: The first state is dp[i][0] which signifies the number of flips required to make all zeroes up to the ith bit.Second state dp[i][1] which signifies the number of flips required to make the current bit 1 such that the conditions given in the question are satisfied. So the required answer will be minimum flips for making the current bit 1 + minimum flips for making all bits after the current bit 0 for all values of i. But if all the bits in the given string are 0 then we don't have to change anything, so we can check the minimum between our answer and the number of flips required to make the string with all zeroes. So we can compute the answer by iterating over all the characters in the string where, answer = min ( answer, dp[i][1] + dp[n-1][0] - dp[i][0])wheredp[i][1] = Minimum number of flips to set current bit to 1dp[n-1][0] - dp[i][0] = Minimum number of flips required to make all bits after i as 0 Below is the implementation of the above approach: C++ //cpp implementation for Minimum number of //flips required in a binary string such //that all the 1’s are together #include <bits/stdc++.h> using namespace std; int minFlip(string a) { //Length of the binary string int n = a.size(); vector<vector<int>> dp(n + 1,vector<int>(2, 0)); //Initial state of the dp //dp[0][0] will be 1 if the current //bit is 1 and we have to flip it dp[0][0] = (a[0] == '1'); //Initial state of the dp //dp[0][1] will be 1 if the current //bit is 0 and we have to flip it dp[0][1] = (a[0] == '0'); for (int i = 1; i < n; i++) { //dp[i][0] = Flips required to //make all previous bits zero //+ Flip required to make current bit zero dp[i][0] = dp[i - 1][0] + (a[i] == '1'); //dp[i][1] = minimum flips required //to make all previous states 0 or make //previous states 1 satisfying the condition dp[i][1] = min(dp[i - 1][0], dp[i - 1][1]) + (a[i] == '0'); } int answer = INT_MAX; for (int i=0;i<n;i++) { answer = min(answer, dp[i][1] + dp[n - 1][0] - dp[i][0]); } //Minimum of answer and flips //required to make all bits 0 return min(answer, dp[n - 1][0]); } //Driver Code int main() { string s = "1100111000101"; cout<<(minFlip(s)); } // This code is contributed by Mohit kumar 29 Java // Java implementation for // Minimum number of flips // required in a binary string // such that all the 1’s are together import java.io.*; import java.util.*; class GFG{ static int minFlip(String a) { // Length of the binary string int n = a.length(); int dp[][] = new int[n + 1][2]; // Initial state of the dp // dp[0][0] will be 1 if // the current bit is 1 // and we have to flip it if(a.charAt(0) == '1') { dp[0][0] = 1 ; } else dp[0][0] = 0; // Initial state of the dp // dp[0][1] will be 1 if // the current bit is 0 // and we have to flip it if(a.charAt(0) == '0') dp[0][1] = 1; else dp[0][1] = 0; for (int i = 1; i < n; i++) { // dp[i][0] = Flips required to // make all previous bits zero // Flip required to make current // bit zero if(a.charAt(i) == '1') { dp[i][0] = dp[i - 1][0] + 1; } else dp[i][0] = dp[i - 1][0]; // dp[i][1] = minimum flips // required to make all previous // states 0 or make previous states // 1 satisfying the condition if(a.charAt(i) == '0') { dp[i][1] = Math.min(dp[i - 1][0], dp[i - 1][1]) + 1; } else dp[i][1] = Math.min(dp[i - 1][0], dp[i - 1][1]); } int answer = Integer.MAX_VALUE; for (int i = 0; i < n; i++) { answer = Math.min(answer, dp[i][1] + dp[n - 1][0] - dp[i][0]); } //Minimum of answer and flips //required to make all bits 0 return Math.min(answer, dp[n - 1][0]); } // Driver code public static void main (String[] args) { String s = "1100111000101"; System.out.println(minFlip(s)); } } // This code is contributed by satvikshrivas26 Python3 # Python implementation for Minimum number of # flips required in a binary string such # that all the 1’s are together def minFlip(a): # Length of the binary string n = len(a) dp =[[0, 0] for i in range(n)] # Initial state of the dp # dp[0][0] will be 1 if the current # bit is 1 and we have to flip it dp[0][0]= int(a[0]=='1') # Initial state of the dp # dp[0][1] will be 1 if the current # bit is 0 and we have to flip it dp[0][1]= int(a[0]=='0') for i in range(1, n): # dp[i][0] = Flips required to # make all previous bits zero # + Flip required to make current bit zero dp[i][0]= dp[i-1][0]+int(a[i]=='1') # dp[i][1] = minimum flips required # to make all previous states 0 or make # previous states 1 satisfying the condition dp[i][1]= min(dp[i-1])+int(a[i]=='0') answer = 10**18 for i in range(n): answer = min(answer, dp[i][1]+dp[n-1][0]-dp[i][0]) # Minimum of answer and flips # required to make all bits 0 return min(answer, dp[n-1][0]) # Driver code s = "1100111000101" print(minFlip(s)) C# // C# implementation for // Minimum number of // flips required in // a binary string such // that all the 1’s are together using System; class GFG{ static int minFlip(string a) { //Length of the binary string int n = a.Length; int [,]dp=new int[n + 1, 2]; //Initial state of the dp //dp[0][0] will be 1 if the current //bit is 1 and we have to flip it dp[0, 0] = (a[0] == '1' ? 1 : 0); //Initial state of the dp //dp[0][1] will be 1 if the current //bit is 0 and we have to flip it dp[0, 1] = (a[0] == '0' ? 1 : 0); for (int i = 1; i < n; i++) { //dp[i][0] = Flips required to //make all previous bits zero //+ Flip required to make current bit zero dp[i, 0] = dp[i - 1, 0] + (a[i] == '1' ? 1 : 0); //dp[i][1] = minimum flips required //to make all previous states 0 or make //previous states 1 satisfying the condition dp[i, 1] = Math.Min(dp[i - 1, 0], dp[i - 1, 1]) + (a[i] == '0' ? 1 : 0); } int answer = int.MaxValue; for (int i = 0; i < n; i++) { answer = Math.Min(answer, dp[i, 1] + dp[n - 1, 0] - dp[i, 0]); } //Minimum of answer and flips //required to make all bits 0 return Math.Min(answer, dp[n - 1, 0]); } // Driver code public static void Main(string[] args) { string s = "1100111000101"; Console.Write(minFlip(s)); } } // This code is contributed by Rutvik_56 JavaScript <script> // Javascript implementation for // Minimum number of flips // required in a binary string // such that all the 1’s are together function minFlip(a) { // Length of the binary string let n = a.length; let dp = new Array(n + 2).fill(0).map((t) => new Array(2).fill(0)) // Initial state of the dp // dp[0][0] will be 1 if // the current bit is 1 // and we have to flip it if (a.charAt(0) == '1') { dp[0][0] = 1; } else dp[0][0] = 0; // Initial state of the dp // dp[0][1] will be 1 if // the current bit is 0 // and we have to flip it if (a.charAt(0) == '0') dp[0][1] = 1; else dp[0][1] = 0; for (let i = 1; i < n; i++) { // dp[i][0] = Flips required to // make all previous bits zero // Flip required to make current // bit zero if (a.charAt(i) == '1') { dp[i][0] = dp[i - 1][0] + 1; } else dp[i][0] = dp[i - 1][0]; // dp[i][1] = minimum flips // required to make all previous // states 0 or make previous states // 1 satisfying the condition if (a.charAt(i) == '0') { dp[i][1] = Math.min(dp[i - 1][0], dp[i - 1][1]) + 1; } else dp[i][1] = Math.min(dp[i - 1][0], dp[i - 1][1]); } let answer = Number.MAX_SAFE_INTEGER; for (let i = 0; i < n; i++) { answer = Math.min(answer, dp[i][1] + dp[n - 1][0] - dp[i][0]); } // Minimum of answer and flips // required to make all bits 0 return Math.min(answer, dp[n - 1][0]); } // Driver code let s = "1100111000101"; document.write(minFlip(s)); // This code is contributed by _saurabh_jaiswal. </script> Output: 4 Time Complexity: O(N) Auxiliary Space: O(N), where N is the length of the string. Comment More infoAdvertise with us Next Article Analysis of Algorithms P pedastrian Follow Improve Article Tags : DSA binary-string Similar Reads Basics & PrerequisitesLogic Building ProblemsLogic building is about creating clear, step-by-step methods to solve problems using simple rules and principles. Itâs the heart of coding, enabling programmers to think, reason, and arrive at smart solutions just like we do.Here are some tips for improving your programming logic: Understand the pro 2 min read Analysis of AlgorithmsAnalysis of Algorithms is a fundamental aspect of computer science that involves evaluating performance of algorithms and programs. Efficiency is measured in terms of time and space.BasicsWhy is Analysis Important?Order of GrowthAsymptotic Analysis Worst, Average and Best Cases Asymptotic NotationsB 1 min read Data StructuresArray Data StructureIn this article, we introduce array, implementation in different popular languages, its basic operations and commonly seen problems / interview questions. An array stores items (in case of C/C++ and Java Primitive Arrays) or their references (in case of Python, JS, Java Non-Primitive) at contiguous 3 min read String in Data StructureA string is a sequence of characters. The following facts make string an interesting data structure.Small set of elements. Unlike normal array, strings typically have smaller set of items. For example, lowercase English alphabet has only 26 characters. ASCII has only 256 characters.Strings are immut 2 min read Hashing in Data StructureHashing is a technique used in data structures that efficiently stores and retrieves data in a way that allows for quick access. Hashing involves mapping data to a specific index in a hash table (an array of items) using a hash function. It enables fast retrieval of information based on its key. The 2 min read Linked List Data StructureA linked list is a fundamental data structure in computer science. It mainly allows efficient insertion and deletion operations compared to arrays. Like arrays, it is also used to implement other data structures like stack, queue and deque. Hereâs the comparison of Linked List vs Arrays Linked List: 2 min read Stack Data StructureA Stack is a linear data structure that follows a particular order in which the operations are performed. The order may be LIFO(Last In First Out) or FILO(First In Last Out). LIFO implies that the element that is inserted last, comes out first and FILO implies that the element that is inserted first 2 min read Queue Data StructureA Queue Data Structure is a fundamental concept in computer science used for storing and managing data in a specific order. It follows the principle of "First in, First out" (FIFO), where the first element added to the queue is the first one to be removed. It is used as a buffer in computer systems 2 min read Tree Data StructureTree Data Structure is a non-linear data structure in which a collection of elements known as nodes are connected to each other via edges such that there exists exactly one path between any two nodes. Types of TreeBinary Tree : Every node has at most two childrenTernary Tree : Every node has at most 4 min read Graph Data StructureGraph Data Structure is a collection of nodes connected by edges. It's used to represent relationships between different entities. If you are looking for topic-wise list of problems on different topics like DFS, BFS, Topological Sort, Shortest Path, etc., please refer to Graph Algorithms. Basics of 3 min read Trie Data StructureThe Trie data structure is a tree-like structure used for storing a dynamic set of strings. It allows for efficient retrieval and storage of keys, making it highly effective in handling large datasets. Trie supports operations such as insertion, search, deletion of keys, and prefix searches. In this 15+ min read AlgorithmsSearching AlgorithmsSearching algorithms are essential tools in computer science used to locate specific items within a collection of data. In this tutorial, we are mainly going to focus upon searching in an array. When we search an item in an array, there are two most common algorithms used based on the type of input 2 min read Sorting AlgorithmsA Sorting Algorithm is used to rearrange a given array or list of elements in an order. For example, a given array [10, 20, 5, 2] becomes [2, 5, 10, 20] after sorting in increasing order and becomes [20, 10, 5, 2] after sorting in decreasing order. There exist different sorting algorithms for differ 3 min read Introduction to RecursionThe process in which a function calls itself directly or indirectly is called recursion and the corresponding function is called a recursive function. A recursive algorithm takes one step toward solution and then recursively call itself to further move. The algorithm stops once we reach the solution 14 min read Greedy AlgorithmsGreedy algorithms are a class of algorithms that make locally optimal choices at each step with the hope of finding a global optimum solution. At every step of the algorithm, we make a choice that looks the best at the moment. To make the choice, we sometimes sort the array so that we can always get 3 min read Graph AlgorithmsGraph is a non-linear data structure like tree data structure. The limitation of tree is, it can only represent hierarchical data. For situations where nodes or vertices are randomly connected with each other other, we use Graph. Example situations where we use graph data structure are, a social net 3 min read Dynamic Programming or DPDynamic Programming is an algorithmic technique with the following properties.It is mainly an optimization over plain recursion. Wherever we see a recursive solution that has repeated calls for the same inputs, we can optimize it using Dynamic Programming. The idea is to simply store the results of 3 min read Bitwise AlgorithmsBitwise algorithms in Data Structures and Algorithms (DSA) involve manipulating individual bits of binary representations of numbers to perform operations efficiently. These algorithms utilize bitwise operators like AND, OR, XOR, NOT, Left Shift, and Right Shift.BasicsIntroduction to Bitwise Algorit 4 min read AdvancedSegment TreeSegment Tree is a data structure that allows efficient querying and updating of intervals or segments of an array. It is particularly useful for problems involving range queries, such as finding the sum, minimum, maximum, or any other operation over a specific range of elements in an array. The tree 3 min read Pattern SearchingPattern searching algorithms are essential tools in computer science and data processing. These algorithms are designed to efficiently find a particular pattern within a larger set of data. Patten SearchingImportant Pattern Searching Algorithms:Naive String Matching : A Simple Algorithm that works i 2 min read GeometryGeometry is a branch of mathematics that studies the properties, measurements, and relationships of points, lines, angles, surfaces, and solids. From basic lines and angles to complex structures, it helps us understand the world around us.Geometry for Students and BeginnersThis section covers key br 2 min read Interview PreparationInterview Corner: All Resources To Crack Any Tech InterviewThis article serves as your one-stop guide to interview preparation, designed to help you succeed across different experience levels and company expectations. Here is what you should expect in a Tech Interview, please remember the following points:Tech Interview Preparation does not have any fixed s 3 min read GfG160 - 160 Days of Problem SolvingAre you preparing for technical interviews and would like to be well-structured to improve your problem-solving skills? Well, we have good news for you! GeeksforGeeks proudly presents GfG160, a 160-day coding challenge starting on 15th November 2024. In this event, we will provide daily coding probl 3 min read Practice ProblemGeeksforGeeks Practice - Leading Online Coding PlatformGeeksforGeeks Practice is an online coding platform designed to help developers and students practice coding online and sharpen their programming skills with the following features. GfG 160: This consists of most popular interview problems organized topic wise and difficulty with with well written e 6 min read Problem of The Day - Develop the Habit of CodingDo you find it difficult to develop a habit of Coding? If yes, then we have a most effective solution for you - all you geeks need to do is solve one programming problem each day without any break, and BOOM, the results will surprise you! Let us tell you how:Suppose you commit to improve yourself an 5 min read Like