Menu driven program in C++ to perform various basic operations on array Last Updated : 12 Jul, 2025 Comments Improve Suggest changes 4 Likes Like Report Prerequisite: Switch Statement in C/C++, Functions in C/C++, Loops in C and C++, C/C++ do-while loop with Examples Write a menu-driven program to perform below various basic operations in the array: Print all the even values in the array.Print all the odd values in the array.Sum & average of elements in the array.Find the maximum and minimum element in the array.Remove duplicates from the array. Approach: Check if a number is odd or even: There are 2 ways to achieve this:By doing Bitwise AND of 1 and that digit if the result comes out to be 1 then the number is odd otherwise even.By its divisibility by 2. A number is said to be odd if it is not divisible by 2, otherwise, it is even.Find the sum and divide the sum by the total number of elements: By iterating through the whole array and adding it to a variable sum. Dividing the sum by total no. of elements to find the average.Find the max and min in the array: Initialize values of min and max as minimum and maximum of the first two elements respectively. Starting from 3rd, compare each element with max and min, and change max and min accordingly. If the element is smaller than min then change min, Else if the element is greater than max then change max, Else ignore the elementRemove the duplicates from the array: Sort the array using the inbuilt sort( ) function. Create an auxiliary array temp[] to store unique elements. Traverse input array and one by one copy unique elements of arr[] to temp[]. Also, keep track of the count of unique elements. Let this count be j. Copy j elements from temp[] to arr[] and return jPrint the array in the reverse: Reverse an array or string Below is the implementation of the above approach: C++ // C++ program for the above approach #include <bits/stdc++.h> using namespace std; // Function to display all the menu in // the current program void menu() { cout << "\n\t\tMENU :"; cout << "\nPress 1 to print even " << "valued elements\n"; cout << "Press 2 to print odd valued" << " elements\n"; cout << "Press 3 to calculate sum " << "and average of elements in " << "the array\n"; cout << "Press 4 to print maximum" << " and minimum element " "in the array\n"; cout << "Press 5 to remove the " << "duplicacy in array \n"; cout << "Press 6 to print array" << " in reverse\n"; cout << "Press 7 to exit\n"; } // Function to print even valued // elements in the array arr[] void even(int arr[], int len) { cout << "Even numbers in the " << "array are - "; for (int i = 0; i < len; i++) { if (arr[i] % 2 == 0) { cout << arr[i] << "\t"; } } } // Function to print odd valued // elements in the array arr[] void odd(int arr[], int len) { cout << "Odd numbers in the " << "array are - "; for (int i = 0; i < len; i++) { if (arr[i] % 2 != 0) { cout << arr[i] << "\t"; } } } // Function to print sum and the // average of elements in array void SumAverage(int arr[], int len) { int sum = 0; for (int i = 0; i < len; i++) { sum += arr[i]; } cout << "\n Sum =" << sum; cout << "\n Average =" << sum / len; } // Function to print maximum and // minimum elements in an array void MaxMin(int arr[], int len) { int max = arr[1], min = arr[0]; // Traverse the array for (int i = 0; i < len; i++) { // Update the maximum if (arr[i] > max) max = arr[i]; // Update the minimum if (arr[i] < min) min = arr[i]; } cout << "Maximum = " << max << "\t"; cout << "Minimum = " << min; } // Function to remove duplicate // elements in an array void RmDuplicacy(int arr[], int n) { if (n == 0 || n == 1) cout << "No Duplicates"; // sorting array using inbuilt // sort() function sort(arr, arr + n); int temp[n]; // Start traversing elements int j = 0; for (int i = 0; i < n - 1; i++) // If current element is not // the same as the next element // then store the current element if (arr[i] != arr[i + 1]) temp[j++] = arr[i]; // Store the last element as whether // it is unique or repeated, it hasn't // stored previously temp[j++] = arr[n - 1]; // Modify original array for (int i = 0; i < j; i++) arr[i] = temp[i]; // j is now the size of the array // without duplicates for (int i = 0; i < j; i++) { cout << arr[i] << " "; } } // Function to print array // in reverse order void Reverse(int arr[], int len) { cout << "\nArray in reverse" << " order:\n "; for (int i = len - 1; i >= 0; i--) { cout << arr[i] << "\t"; } } // Driver Code int main() { int arr[100], i, num, choice; printf("Enter the size of " "an array :\n"); cin >> num; printf("Enter the elements of " "the array :\n"); for (i = 0; i < num; i++) { cin >> arr[i]; } do { cout << "\n"; menu(); cout << "\nEnter your " << "choice:\n "; cin >> choice; switch (choice) { case 1: even(arr, num); break; case 2: odd(arr, num); break; case 3: SumAverage(arr, num); break; case 4: MaxMin(arr, num); break; case 5: RmDuplicacy(arr, num); break; case 6: Reverse(arr, num); break; case 7: exit(0); break; default: cout << "INVALID CHOICE :-("; } } while (choice != 7); return 0; } Output: Create Quiz Comment J jt9999709701 Follow 4 Improve J jt9999709701 Follow 4 Improve Article Tags : Searching Mathematical Technical Scripter DSA Arrays Technical Scripter 2020 Reverse Arrays Menu driven programs +5 More Explore DSA FundamentalsLogic Building Problems 2 min read Analysis of Algorithms 1 min read Data StructuresArray Data Structure 3 min read String in Data Structure 2 min read Hashing in Data Structure 2 min read Linked List Data Structure 3 min read Stack Data Structure 2 min read Queue Data Structure 2 min read Tree Data Structure 2 min read Graph Data Structure 3 min read Trie Data Structure 15+ min read AlgorithmsSearching Algorithms 2 min read Sorting Algorithms 3 min read Introduction to Recursion 15 min read Greedy Algorithms 3 min read Graph Algorithms 3 min read Dynamic Programming or DP 3 min read Bitwise Algorithms 4 min read AdvancedSegment Tree 2 min read Binary Indexed Tree or Fenwick Tree 15 min read Square Root (Sqrt) Decomposition Algorithm 15+ min read Binary Lifting 15+ min read Geometry 2 min read Interview PreparationInterview Corner 3 min read GfG160 3 min read Practice ProblemGeeksforGeeks Practice - Leading Online Coding Platform 1 min read Problem of The Day - Develop the Habit of Coding 5 min read Like